android sqlite插入到哪里 [英] android sqlite insert into where
本文介绍了android sqlite插入到哪里的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
我想插入现有应用数据表的应用类别.我不知道我这样做是否正确,但在我正在做的事情中,我也遇到了这个错误.
i want to insert category of the application of the existing table of application data. I do not know if im doing it correct, but in what i am doing i get this error as well.
我该怎么做才能正确?
主要活动
AlertDialog.Builder builder = new AlertDialog.Builder(
MainActivity.this);
builder.setTitle("Please Select Category of : " + AppName);
builder.setItems(shareItems,
new DialogInterface.OnClickListener() {
@Override
public void onClick(DialogInterface dialog, int item) {
// TODO Auto-generated method stub
String itemz = String.valueOf(shareItems[item]);
mySQLiteAdapter.insertcategory(AppName, itemz);
}
});
AlertDialog shareAlert = builder.create();
shareAlert.show();
处理程序
public long insertcategory(String AppName, String itemz) {
// TODO Auto-generated method stub
Cursor crack = sqlitedb.rawQuery("INSERT INTO " + KEY_CATEGORY
+ " VALUES ( ' " + itemz + " ' ) WHERE " + KEY_NAME
+ " LIKE ?", new String[] { "%" + AppName+ "%" });
return 0;
}
更新的查询这是我用来更新表的.itemz 的值是游戏",但没有更新
updated query This is what i used to update the table. itemz gets the value as 'Game' but it does not getting updated
public long insertcategory(String AppName, String itemz) {
// TODO Auto-generated method stub
ContentValues values = new ContentValues();
values.put(KEY_CATEGORY, itemz);
return sqlitedb.update(MYDATABASE_TABLE, values, KEY_NAME + " LIKE ?",
new String[] { "%" + AppName + "%" });
}
表创建为
private static final String SCRIPT_CREATE_DATABASE = "create table "
+ MYDATABASE_TABLE + " (" + KEY_ID
+ " integer primary key autoincrement, " + KEY_NAME
+ " text not null, " + KEY_PACK + " text not null, " + KEY_PERM
+ " text not null, " + KEY_LEVEL + " text not null, "
+ KEY_CATEGORY + " text);";
推荐答案
INSERT 命令没有 WHERE 子句,因为它插入了一个全新的记录.
The INSERT command does not have a WHERE clause because it inserts a completely new record.
您似乎想设置/更改现有记录中的值.这将通过 UPDATE 命令完成:
It appears you want to set/change the value in an existing record. This would be done with an UPDATE command:
UPDATE MyTable SET category = 'Entertainment' WHERE name LIKE ?
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