PHP - 搜索字符串为一个特定的单词阵列，并匹配一个可选的+或 - [英] PHP - Search String for a Specific Word Array and Match with an Optional + or -

问题描述

我需要寻找一个字符串一个特定的词，并有比赛是一个变量。我有话的具体列表中的数组：

I need to search a string for a specific word and have the match be a variable. I have a specific list of words in an array:

$names = array ("Blue", "Gold", "White", "Purple", "Green", "Teal", "Purple", "Red");

$drag = "Glowing looks to be +Blue.";

$match = "+Blue";

echo $match

+Blue

我需要做的是搜索 $拖与 $名称并找到匹配的选项 + 或 - 字符，并有 $匹配成为结果

What I need to do is search $drag with the $names and find matches with an option + or - character and have $match become the result.

推荐答案

与加入阵列的条款建立一个正规的前pression | ，并添加可选的 [ - +] 开头：

Build a regular expression by joining the terms of the array with |, and adding an optional [-+] at the beginning:

$names = array ("Blue", "Gold", "White", "Purple", "Green", "Teal", "Purple", "Red");

$drag = "Glowing looks to be +Blue.";

$pattern = '/[-+]?(' . join($names, '|') . ')/';

$matches = array();

preg_match($pattern, $drag, $matches);

$matches = $matches[0];

var_dump($matches);

输出：

string(5) "+Blue"

如果你想确保你只匹配 +蓝，而不是 +风信子，您可以添加单词边界比赛中， \\ b ，以正则表达式的开始/结束。

If you want to insure that you match only +Blue and not +Bluebell, you can add word boundary matches, \b, to the beginning/end of the regex.

如果你想找到的所有单词的所有实例，使用 preg_match_all 代替。

If you want to find all instances of all words, use preg_match_all instead.

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