查找在数组中最长的单词/字符串 [英] Find the longest word/string in an array

问题描述

我刚开始学习JavaScript。我想写一个JavaScript找到并打印在数组中最长的单词。我想出了下面的code：

  VAR长字= [佩内洛普，约翰尼，Aubumayang，捷克斯洛伐克，斯洛文尼亚]
变种最长= 0;
对于（VAR I = 0; I＆LT; longWords.length;我++）{
如果（最长＆LT;长字[I]。长度）{
    最长=长字[I]
  }
}的console.log（最长）
 

问题是，它总是最终打印数组中的第一个元素。此装置 =最长的长字[0] 。现在，当我换行 =最长的长字[I] 到 =最长的长字[I]。长度我得到的算上最长字符。请告诉我，为什么它没有工作，我怎么能使用为循环做到这一点。

解决方案

 如果（最长＆LT;长字[I]。长度）{
 

也许应该是

 如果（longest.length＆LT;长字[I]。长度）{
 

I just started learning JavaScript. I am trying to write a JavaScript to find and print the longest word in an Array. I came up with the code below:

var longWords = ["Penelope", "Johny", "Aubumayang", "Czechoslovakia", "Slovenia"]
var longest = 0;
for (var i = 0; i < longWords.length; i++) {
if (longest < longWords[i].length) {
    longest = longWords[i];
  }
}

console.log(longest)

The problem is it always end up printing the first element in the array. which means longest = longWords[0]. Now when I change the line longest = longWords[i] to longest = longWords[i].length I get the count of the longest character. Please tell me why it didn't work and how I can do this using the for loop.

解决方案

if (longest < longWords[i].length) {

Should probably be

if (longest.length < longWords[i].length) {

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