有 5 的 SQL Server 舍入问题 [英] SQL Server Rounding Issue where there is 5

问题描述

据我所知，当四舍五入数为 5 时，根据数学四舍五入应该如下工作.

As far as i know according to mathematics rounding should work as below when rounding number is 5.

2.435 => 2.44 (Round Up, if rounding to digit(3) is odd number)
2.445 => 2.44 (Round Down, if rounding to digit(4) is even number)

如果求和没问题，

2.435 + 2.445 =  4.88
2.44 + 2.44 = 4.88 

我很确定在 .Net 中也有这样的舍入方式.

I'm pretty sure in .Net also rounding works like this.

但在 SQL Server 中，5 总是四舍五入，根据数学计算是不正确的.

But in SQL server, 5 is always rounding up which is not correct according to maths.

SELECT round(2.345, 2)  = 2.35
SELECT round(2.335, 2) => 2.34

这导致四舍五入值的总和存在 1 美分的差异.

this results to 1 cent discrepancies in summation of rounded values.

2.345 + 2.335 = 4.68
2.35 + 2.34 = 4.69 => which is not correct

我已经尝试过使用小数和货币数据类型.

I have tried this with decimal and money data types.

我做错了吗?有没有办法解决这个问题?

Am i doing something wrong? Is there a work around for this?

推荐答案

如果您确实想在 SQL Server 中使用银行家的舍入...

If you do want to use banker's rounding in SQL Server...

CREATE FUNCTION BankersRounding(@value decimal(36,11), @significantDigits INT)        
RETURNS MONEY        
AS        
BEGIN        
    -- if value = 12.345 and signficantDigits = 2...        

    -- base = 1000        
    declare @base int = power(10, @significantDigits + 1)        


    -- roundingValue = 12345        
    declare @roundingValue decimal(36,11) = floor(abs(@value) * @base)        
    -- roundingDigit = 5        
    declare @roundingDigit int = @roundingValue % 10        

    -- significantValue = 1234        
    declare @significantValue decimal(36,11) = floor(@roundingValue / 10)        
    -- lastSignificantDigit = 4        
    declare @lastSignificantDigit int = @significantValue % 10        


    -- awayFromZero = 12.35        
    declare @awayFromZero money = (@significantValue + 1) / (@base / 10)        
    -- towardsZero = 12.34        
    declare @towardsZero money = @significantValue / (@base / 10)        

    -- negative values handled slightly different        
    if @value < 0        
    begin        
        -- awayFromZero = -12.35        
        set @awayFromZero = ((-1 * @significantValue) - 1) / (@base / 10)        
        -- towardsZero = -12.34        
        set @towardsZero = (-1 * @significantValue) / (@base / 10)        
    end        

    -- default to towards zero (i.e. assume thousandths digit is 0-4)        
    declare @rv money = @towardsZero        
    if @roundingDigit > 5        
        set @rv = @awayFromZero  -- 5-9 goes away from 0        
    else if @roundingDigit = 5         
    begin        
        -- 5 goes to nearest even number (towards zero if even, away from zero if odd)        
        set @rv = case when @lastSignificantDigit % 2 = 0 then @towardsZero else @awayFromZero end        
    end        

    return @rv        

end        

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