如何在 sql server 2008 中调用标量函数 [英] how to call scalar function in sql server 2008

问题描述

我创建了一个标量函数，它已成功创建，但是当我使用 select 语句调用该函数时，它显示无效的对象名称dbo.fun_functional_score".

I have created a Scalar Functions, it was created successfully, but when I call the function using select statement, it says Invalid object name 'dbo.fun_functional_score'.

我的功能:

 ALTER function [dbo].[fun_functional_score] (@phy_id varchar(20))
 returns  varchar(50)

as
begin 

declare @level_initial int, @level_current int

-- initial functional score
set @level_initial=(SELECT pflag.fun_level
FROM tbl_phy_demographic_details as [phy] 
    inner join tbl_all_purple_flag_level as [pflag] on phy.Demographic_id=pflag.Id 
WHERE phy.Physicion_id=@phy_id
    and pflag.visited_count=(select MAX(visited_count)-1 from tbl_all_purple_flag_level ))


-- current functional score
set @level_current=(SELECT pflag.fun_level
FROM tbl_phy_demographic_details as [phy] 
    inner join tbl_all_purple_flag_level as [pflag] on phy.Demographic_id=pflag.Id 
WHERE phy.Physicion_id=@phy_id
    and pflag.visited_count=(select MAX(visited_count) from tbl_all_purple_flag_level ))


--to calculate functional score
declare @fun_level varchar(20),@result varchar(50)

set  @fun_level=@level_current-@level_initial;

 if @fun_level = 0   set @result='Maintained' 
if @fun_level = '-1'  set @result='Minor Improvement' 
if @fun_level = '-2'  set @result='Moderate Improvement' 
if @fun_level = '-3'  set @result='Significant Improvement' 
if @fun_level =  '-4'  set @result='Substantial Improvement' 
if @fun_level =  '1'  set @result='Minor Reduction' 
if @fun_level =  '2'  set @result='Moderate Reduction' 
if @fun_level =  '3'  set @result='Significant Reduction' 
if @fun_level =  '4'  set @result='Substantial Reduction' 




return @result

end

我用这个选择来调用

 select * from dbo.fun_functional_score('01091400003') as [er]

或

 select * from dbo.fun_functional_score('01091400003') 

都显示错误无效的对象名称'dbo.fun_functional_score'."

both showing error "Invalid object name 'dbo.fun_functional_score'. "

我出错的地方.谁能帮帮我...

where i made error . can anyone help me...

推荐答案

你的语法是表值函数的，它返回一个结果集，可以像表一样查询.对于标量函数做

Your syntax is for table valued function which return a resultset and can be queried like a table. For scalar function do

 select  dbo.fun_functional_score('01091400003') as [er]

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