比较两个数组对象 [英] Comparing two array of objects

问题描述

我想比较两个数组对象。下面是我的code。

I am trying to compare two array of objects. Below is my code.

var result = identical([
    {"depid": "100", "depname": ""},
    {"city": "abc", "state": "xyz"},
    {"firstName": "John", "lastName": "Doe", "contactno": {"ph": 12345, "mob": 485428428}}
], [
    {"firstName": "John", "lastName": "Doe", "contactno": {"ph": 12345, "mob": 485428428}},
    {"depid": "100", "depname": ""},
    {"city": "abc", "state": "xyz"}
]);

console.log(result); // returns false

function identical(a, b) {
    function sort(object) {
      if (typeof object !== "object" || object === null) {
            return object;
        }
        return Object.keys(object).sort().map(function (key) {
            return {
                key: key,
                value: sort(object[key])
            };
        });
    }

    return JSON.stringify(sort(a)) === JSON.stringify(sort(b));
};

我想知道为什么我收到的结果为假，而对比上述两个数组对象。

I want to know why I am getting result as false while comparing the above two array of objects.

如果我通过下面的对象，其结果是真实的。

If I pass the below object, the result is true

var result = identical([
    {"firstName": "John", "lastName": "Doe", "contactno": {"ph": 12345, "mob": 485428428}},
    {"depid": "100", "depname": ""},
    {"city": "abc", "state": "xyz"}
], [
    {"firstName": "John", "lastName": "Doe", "contactno": {"ph": 12345, "mob": 485428428}},
    {"depid": "100", "depname": ""},
    {"city": "abc", "state": "xyz"}
]);

如何基于单独键和没有看到对象的顺序比较？

How to compare based on keys alone and without seeing the order of objects ?

推荐答案

一我找到了解决方案，是定义一个函数来测试对象的平等，那么你需要调用该函数用于对每一个元素数组。这code正常工作对我来说：

One of the solutions I found, is to define a function to test the equality of the objects, and then you need to call that function for each element on the array. this code works fine for me:

Object.prototype.equals = function(x) {
        for(p in this) {
            switch(typeof(this[p])) {
                    case 'object':
                            if (!this[p].equals(x[p])) { return false }; break;
                    case 'function':
                            if (typeof(x[p])=='undefined' || (p != 'equals' && this[p].toString() != x[p].toString())) { return false; }; break;
                    default:
                            if (this[p] != x[p]) { return false; }
            }
        }
        for(p in x) {
            if(typeof(this[p])=='undefined') {return false;}
        }

        return true;
    }

来源：<一个href=\"http://stackoverflow.com/questions/1068834/object-comparison-in-javascript#answer-1068883\">Object在JavaScript中比较

    function identical (arr1, arr2) {

        if(arr1.length != arr2.length) {
            return false;
        }

        var exists = arr1.length;
        for(var i = 0; i<arr1.length; i++) {
            for(var j =0; j<arr2.length ; j++) {
                if(Object.keys(arr1[i]).equals(Object.keys(arr2[j]))) {
                   exists--;
                }
            }
        }

        return !exists;
    }

现在这个code的结果是真正

Now the result of this code is true

var result = identical([
    {"firstName": "John", "lastName": "Doe", "contactno": {"ph": 12345, "mob": 485428428}},
    {"depid": "100", "depname": ""},
    {"city": "abc", "state": "xyz"}
], [
    {"firstName": "John", "lastName": "Doe", "contactno": {"ph": 12345, "mob": 485428428}},
    {"depid": "100", "depname": ""},
    {"city": "abc", "state": "xyz"}
]);

编辑：

要比较只有按键，你需要使用：

To compare only keys, you need to use :

Object.keys(arr1[i]).equals(Object.keys(arr2[j])

而不是

arr1[i].equals(arr2[j])

我做的code以上的更新。

I made the update on the code above.

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