为索引列表生成 CREATE 脚本 [英] Generate CREATE scripts for a list of indexes

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本文介绍了为索引列表生成 CREATE 脚本的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!

问题描述

作为排序规则更改练习的一部分,我有一个需要删除然后重新创建的索引列表 (122).如何重新创建这些索引,而不必每次都通过 GUI 并将其编写到查询窗口中?

As part of a collation changing exercise, I have a list of indexes (122) that needs to be dropped and then re-created. How can I re-create these indexes without having to go through the GUI and scripting it to a query window each time?

我的索引列表是从这个脚本中获得的

My list of indexes is obtained from this script

WITH indexCTE AS
    (   
    SELECT Table_Name, Column_Name, Collation_Name 
    FROM information_schema.columns 
    WHERE Collation_Name IS NOT NULL AND Collation_Name = 'Modern_Spanish_CI_AS'
    ), 
    indexCTE2 AS
    (
    SELECT i.Name [Index Name], OBJECT_NAME(i.object_ID) [Table Name], c.Name [Column Name]
    FROM sys.indexes i 
    INNER JOIN sys.index_columns ic ON i.index_id = ic.index_id AND i.object_id = ic.object_id
    INNER JOIN sys.columns c ON ic.column_id = c.column_id AND ic.object_id = c.OBJECT_ID
    WHERE EXISTS (SELECT 1 FROM indexCTE t1 WHERE t1.Table_Name = OBJECT_NAME(i.object_ID) AND t1.Column_Name = c.Name)
    ) SELECT * FROM indexCTE2

如您所知,我仍然是一名初级 DBA,所以请耐心等待!

As you can probably tell, I'm still a Jr. DBA so please be patient with me!

谢谢!

推荐答案

你很接近,我会说 - 我试过这个,你能验证这是否适合你并向你显示预期的 122 个要重新创建的索引??

You're pretty close, I'd say - I tried this, can you verify if this works for you and shows you the expected 122 indices to be recreated??

更新:添加了用于确定 CLUSTERED 与 NONCLUSTERED 索引类型的功能,并将包含的列添加到索引定义中.

UPDATE: added functionality to determine CLUSTERED vs. NONCLUSTERED index type, and to add INCLUDEd columns to the index definition.

WITH indexCTE AS
(
    SELECT DISTINCT 
        i.index_id, i.name, i.object_id
    FROM 
        sys.indexes i 
    INNER JOIN
        sys.index_columns ic 
           ON i.index_id = ic.index_id AND i.object_id = ic.object_id
    WHERE 
        EXISTS (SELECT * FROM sys.columns c 
                 WHERE c.collation_name = 'Modern_Spanish_CI_AS' 
                 AND c.column_id = ic.column_id AND c.object_id = ic.object_id)
), 
indexCTE2 AS
(
    SELECT 
        indexCTE.name 'IndexName', 
        OBJECT_NAME(indexCTE.object_ID) 'TableName',
        CASE indexCTE.index_id 
          WHEN 1 THEN 'CLUSTERED'
          ELSE 'NONCLUSTERED'
        END AS 'IndexType', 
        (SELECT DISTINCT c.name + ','
         FROM 
            sys.columns c 
         INNER JOIN
            sys.index_columns ic 
               ON c.object_id = ic.object_id AND ic.column_id = c.column_id AND ic.Is_Included_Column = 0
         WHERE
            indexCTE.OBJECT_ID = ic.object_id 
            AND indexCTE.index_id = ic.index_id 
         FOR XML PATH('')
        ) ixcols,
        ISNULL(
        (SELECT DISTINCT c.name + ','
         FROM 
            sys.columns c 
         INNER JOIN
            sys.index_columns ic 
               ON c.object_id = ic.object_id AND ic.column_id = c.column_id AND ic.Is_Included_Column = 1
         WHERE
            indexCTE.OBJECT_ID = ic.object_id 
            AND indexCTE.index_id = ic.index_id 
         FOR XML PATH('')
        ), '') includedcols
    FROM 
        indexCTE
) 
SELECT 
    'CREATE ' + IndexType + ' INDEX ' + IndexName + ' ON ' + TableName + 
        '(' + SUBSTRING(ixcols, 1, LEN(ixcols)-1) + 
        CASE LEN(includedcols)
          WHEN 0 THEN ')'
          ELSE ') INCLUDE (' + SUBSTRING(includedcols, 1, LEN(includedcols)-1) + ')'
        END
FROM 
   indexCTE2
ORDER BY 
   TableName, IndexName

您是否得到了您正在寻找的 CREATE INDEX 语句??

Do you get the CREATE INDEX statements you're looking for??

马克

这篇关于为索引列表生成 CREATE 脚本的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!

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