具有汇总逻辑的递归sql函数? [英] recursive sql function with rollup logic?
问题描述
我有一个 SQL,它使用递归 CTE 扩展自引用员工表,构建了按用户和严重性级别聚合的缺陷结果集.
i have a SQL that using a recursive CTE to expand a self-referancing employees table builds a result set of defects aggregated by user and severity level.
这是我的 CTE:
ALTER FUNCTION [dbo].[fnGetEmployeeHierarchyByUsername]
(
@NTID varchar(100) = null
)
RETURNS TABLE
AS
RETURN
(
WITH yourcte AS
(
SELECT EmployeeId, ManagerNTID, ManagerID, NTID, FullName--, Name
FROM Employees
WHERE NTID = @NTID
UNION ALL
SELECT e.EmployeeId, e.ManagerNTID, e.ManagerID, e.NTID, e.FullName--, e.Name
FROM Employees e
JOIN yourcte y ON e.ManagerNTID = y.NTID
)
SELECT EmployeeId, ManagerID, NTID, FullName--, Name
FROM yourcte
)
这是我的用户聚合缺陷的 SQL:
here is my SQL for aggregating defects by the user:
SELECT e.FullName, Urgent, High, Medium, Low
FROM fnGetEmployeeHierarchyByUsername ('ssalvati') e
LEFT OUTER JOIN(
SELECT [AssignedTo],
SUM([1-Urgent]) AS Urgent,
SUM([2-High]) AS High,
SUM([3-Medium]) AS Medium,
SUM([4-Low]) AS Low
FROM (SELECT [AssignedTo],[BusinessSeverity] FROM Defects WHERE Status <> 'Closed') D
PIVOT (COUNT([BusinessSeverity]) FOR [BusinessSeverity] IN ([1-Urgent],[2-High],[3-Medium],[4-Low])) V
GROUP BY [AssignedTo]) AS def
ON e.ntid = def.[AssignedTo]
我想要一个以用户名作为参数的 porc 并生成一个类似于上面的 SQL 的结果,但有 2 个增强:
i want to have a porc that takes a username as a param and generates a result like the SQL above but with 2 enhancements:
我需要它列出作为参数传入的用户,以作为结果集的第一条记录列出.
i need it to list the user passed in as a param to be listed as the first record of the result-set.
我需要向经理报告的员工只显示一层深度,而不是显示完整的树.第一级应该是所有底层缺陷的汇总,这些缺陷分配给汇总为所有一级用户的人员.换句话说,我不想像现在这样在管理器下显示一整棵树,我需要它只显示一个深度,但所有级别的缺陷总和.
i need the employees that report into the manager to show only one level deep and not show the full tree. the first level should be a roll up of all the underlying defects assigned to people who roll up into all the level one users. in other words i dont want to show a entire tree under the manager like it is now, i need it to show only one level deep but with a sum of defects for all the levels.
想法?
推荐答案
这里有一个很长的虚拟方法.我有它的工作,但解决方案可能会更好.我希望有人会发布一个 SQL2005 方法来完成这项工作...
here is the long dummy way of doing it. i have it working but the solution could be much better. i am hoping someone will post a SQL2005 way of getting this done...
alter PROC sel_DefectReportByManagerNTID_rollup
(@ManagerNTID NVARCHAR(100))
AS
CREATE TABLE #DefectCounts
(
id INT IDENTITY(1, 1) ,
MgrRolledInto NVARCHAR(100) NULL,
AltBusinessSeverity NVARCHAR(100) NULL,
DefectCount INT NULL
);
CREATE TABLE #directReports
(
pk INT IDENTITY(1, 1) ,
directReportNTID NVARCHAR(100) NULL
);
INSERT INTO #directReports
SELECT NTID FROM Employees WHERE ManagerNTID = @ManagerNTID
--select * from #directReports
DECLARE @maxPK INT;
SELECT @maxPK = MAX(PK) FROM #directReports
DECLARE @pk INT;
SET @pk = 1
INSERT INTO #DefectCounts (MgrRolledInto,AltBusinessSeverity,DefectCount)
SELECT @ManagerNTID, d.AltBusinessSeverity, COUNT(*)
FROM Defects d
JOIN StatusCode C ON C.CodeName = d.Status AND c.scid = 10
WHERE d.AssignedTo = @ManagerNTID
GROUP BY d.AltBusinessSeverity
WHILE @pk <= @maxPK
BEGIN
/* Get one direct report at a time to aggregate their defects under them... */
DECLARE @dirRptNTID NVARCHAR(100);
SET @dirRptNTID = (SELECT directReportNTID
FROM #directReports
WHERE PK = @pk)
INSERT INTO #DefectCounts (MgrRolledInto,AltBusinessSeverity,DefectCount)
SELECT @dirRptNTID, d.AltBusinessSeverity, COUNT(*)
FROM Defects d
JOIN StatusCode C ON C.CodeName = d.Status AND c.scid = 10
JOIN (SELECT * FROM fnGetEmployeeHierarchyByUsername(@dirRptNTID) ) emp ON emp.NTID = d.AssignedTo
WHERE d.AssignedTo IS NOT NULL
GROUP BY d.AltBusinessSeverity
SELECT @pk = @pk + 1
END
SELECT e.FullName,
isnull(Urgent,0) as Urgent,
isnull(High,0) as High,
isnull(Medium,0) as Medium,
isnull(Medium3000,0) as Medium3000,
isnull(Low,0) as Low
FROM ( select * from fnGetEmployeeHierarchyByUsername (@ManagerNTID) where depth <= 1) e
left outer join (
SELECT MgrRolledInto,
SUM([1-Urgent]) AS Urgent,
SUM([2-High]) AS High,
SUM([3-Medium]) AS Medium,
SUM([3-Medium (3000)]) AS Medium3000,
SUM([4-Low]) AS Low
FROM #DefectCounts dfs
PIVOT
(sum(DefectCount) FOR AltBusinessSeverity IN ([1-Urgent],[2-High],[3-Medium],[3-Medium (3000)],[4-Low])) V
GROUP BY MgrRolledInto
) def_data on def_data.MgrRolledInto = e.NTID
order by e.depth
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