SQL Server 相当于 ORACLE INSTR [英] SQL Server Equivalent to ORACLE INSTR

问题描述

我想知道在 SQL Server 中是否有与 Oracle INSTR 函数等效的函数?
我知道有 CHARINDEX 和 PATINDEX，但是使用 Oracle 版本我还可以指定我要查找的字符的第 N 个外观.

I wanted to know if in SQL Server there is an equivalent to the Oracle INSTR function?
I know that there is CHARINDEX and PATINDEX, but with the Oracle version I can also specify the Nth appearance of the character(s) I am looking for.

Oracle INSTR:

instr( string1, string2 [, start_position [, **nth_appearance** ] ] )

CHARINDEX 几乎让我到达那里，但我想让它从字符串中字符的 nth_appearance 开始.>

The CHARINDEX almost gets me there, but I wanted to have it start at the nth_appearance of the character in the string.

推荐答案

您发现 nth_appearance 在 SQL Server 中不存在.

You were spot on that nth_appearance does not exist in SQL Server.

无耻地复制一个函数(与 SQL Server 中带有 4 个参数的 Oracle 的 INSTR 等效)为您的问题创建(请注意，@Occurs 的使用方式与 Oracle 中的不同 - 您不能指定第三次出现"，但是出现 3 次"):

Shamelessly copying a function (Equivalent of Oracle's INSTR with 4 parameters in SQL Server) created for your problem (please note that @Occurs is not used the same way as in Oracle - you can't specify "3rd appearance", but "occurs 3 times"):

CREATE FUNCTION udf_Instr
    (@str1 varchar(8000), @str2 varchar(1000), @start int, @Occurs int)
RETURNS int
AS
BEGIN
    DECLARE @Found int, @LastPosition int
    SET @Found = 0
    SET @LastPosition = @start - 1

    WHILE (@Found < @Occurs)
    BEGIN
        IF (CHARINDEX(@str1, @str2, @LastPosition + 1) = 0)
            BREAK
          ELSE
            BEGIN
                SET @LastPosition = CHARINDEX(@str1, @str2, @LastPosition + 1)
                SET @Found = @Found + 1
            END
    END

    RETURN @LastPosition
END
GO

SELECT dbo.udf_Instr('x','axbxcxdx',1,4)
GO


DROP FUNCTION udf_Instr
GO

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