次平均阵列作为Ruby字符串 [英] Average array of times as strings in Ruby

问题描述

我有一个数组：

 数组= [零时00分31秒，零时00分52秒，0点01分05秒，0点零零分55秒，0： 01:33，〇时00分05秒，0:00:01，
      0时05分10秒，0点02分40秒，0点03分03秒，0点01分33秒，0:00:00]
 

和我需要的所有平均时代的数组中不等于0:00:00。 0:00:00应该只是扔出去。

什么是做到这一点的最好方法是什么？我目前通过数组循环，清除所有的 0:00:00 值，把字符串转换为整数，做一个平均 - 但好像很多code代表什么，我试图做的。

解决方案

 （SZ = {array.reject | T |牛逼=='〇点零零分00秒'}）。
            图{| T | Time.parse T】。
            减少（0）{| A，T | A + = t.to_i} .to_f / sz.size
 

您想将这些东西放到功能操作。拒绝你不需要的东西，那么作用于其余部分。

在这里，减少是一个可行的方式来获得一个数组平均和前面已经回答了。

---

下面是稍微更简洁是另一种选择，稍微隐晦

 （SZ = {array.reject | T |牛逼=='0:00:00'}）。
            图{| T | Time.parse（T）.to_i}。
            减少（+）。to_f / sz.size
 

I have an array:

array = ["0:00:31", "0:00:52", "0:01:05", "0:00:55", "0:01:33", "0:00:05", "0:00:01", 
      "0:05:10", "0:02:40", "0:03:03", "0:01:33", "0:00:00"]

and I need to average all of the times in the array that are not equal to "0:00:00". "0:00:00" should just be thrown out.

What's the best way to do this? I'm currently looping through the array, removing all of the 0:00:00 values, turning the strings into integers and doing an average - But it seems like a lot of code for what I'm trying to do.

解决方案

(sz = array.reject    {|t| t == '0:00:00' }).
            map       {|t| Time.parse t   }.
            reduce(0) {|a, t| a += t.to_i }.to_f / sz.size

You want to group these things into functional operations. Reject the stuff you don't need, then act on the rest.

Here, reduce is a viable way to get an array average, and has been answered before.

---

here is an alternative that is slightly more concise, slightly more cryptic

(sz = array.reject {|t| t == '0:00:00'     }).
            map    {|t| Time.parse(t).to_i }.
            reduce(:+).to_f / sz.size

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