返回连续日期的临时表 [英] Return temp table of continuous dates

问题描述

我需要创建一个返回连续日期表的函数.我会在一分钟内通过最大日期.

I need to create a function that returns a table of continuous dates. I would pass in a min & max date.

我希望它能够像这样被调用:

I expect it to be able to be called like this:

SELECT * FROM GetDates('01/01/2009', '12/31/2009')

我目前有一个执行此操作的存储过程，但要求发生了变化，现在我需要在联合中包含返回的数据:

I currently have a stored proc that does this, but requirements changed and now I need to do include the returned data from within a union:

 with mycte as
(
     select cast(@minDate as datetime) DateValue
     union all
     select DateValue + 1
     from    mycte   
     where   DateValue + 1 <= @maxDate
 )
 select DateValue
 from    mycte
option (maxrecursion 1000)

然而，问题是我需要将递归设置为大于 100.根据 Gail Erickson [MS] 在 eggheadcafe，目前不支持.

The problem, however, is that I need to set the recursion to be greater than 100. According to a post by Gail Erickson [MS] on eggheadcafe, this is not currently supported.

如果不创建一个真正的(非临时) 表，其中只有日期，有没有办法做到这一点?

Without creating a real (not temporary) table with just date in it, is there a way to do this?

我使用的是 SqlServer2005.

I am using SqlServer2005.

推荐答案

您最好的选择是实际拥有一个实际的日期表.即使在很长一段时间内也没有那么多，而且比从临时表或递归 ctes 中实时实现它们要快得多.

Your best option is to actually have a physical table of dates. There aren't that many for even long periods, and will be much faster than materializing them on-the-fly from temp tables or recursive ctes.

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