SQL SERVER 2005 中的多重搜索选项 [英] Multiple Search Option in SQL SERVER 2005

问题描述

我有一个要求.

假设Test1，Test2，我必须执行类似的操作.

Given say Test1,Test2, I have to perform a like operation.

类似的东西

select * from tblname where column_name like('Test1%','Test2%');

即这些字符串以逗号分隔

i.e. these strings are comma separated

我该如何解决这个问题?

How do I solve this?

这是在 SQL SERVER 2005 中.

This is in SQL SERVER 2005.

提前致谢

推荐答案

Sql server 2005，试试这个

Sql server 2005, try this

--Lookup Table
DECLARE @Values TABLE(
        Column_Name VARCHAR(MAX)
)

INSERT INTO @Values (Column_Name) SELECT 'A'
INSERT INTO @Values (Column_Name) SELECT 'B'
INSERT INTO @Values (Column_Name) SELECT 'ATADA'
INSERT INTO @Values (Column_Name) SELECT 'TADAA'
INSERT INTO @Values (Column_Name) SELECT 'Test123A'
INSERT INTO @Values (Column_Name) SELECT '1Test123A'

--Lookup string and delim
DECLARE @LookupString VARCHAR(MAX)
DECLARE @Delim VARCHAR(1)

SET @LookupString = 'Test1,Test2,TADA'
SET @Delim = ',';

--CREATE A LOOKUP TABLE FOR SPLIT STRINGS
WITH substrings (Val, Remainder) AS(
    SELECT  CASE WHEN CHARINDEX(@Delim,@LookupString) = 0 THEN @LookupString ELSE LEFT(@LookupString,CHARINDEX(@Delim,@LookupString)-1) END,
            CASE WHEN CHARINDEX(@Delim,@LookupString) = 0 THEN '' ELSE RIGHT(@LookupString,LEN(@LookupString) - CHARINDEX(@Delim,@LookupString)) END
    UNION ALL 
    SELECT  CASE WHEN CHARINDEX(@Delim,Remainder) = 0 THEN Remainder ELSE LEFT(Remainder,CHARINDEX(@Delim,Remainder)-1) END,
            CASE WHEN CHARINDEX(@Delim,Remainder) = 0 THEN '' ELSE RIGHT(Remainder,LEN(Remainder) - CHARINDEX(@Delim,Remainder)) END
    FROM substrings
    WHERE CHARINDEX(@Delim,Remainder) >= 0 AND Val != '' AND Remainder != ''
)
SELECT  v.Column_Name,
        substrings.Val
FROM    @Values v INNER JOIN
        substrings ON v.Column_Name LIKE substrings.Val + '%'

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