在 SQL Server 中计算排除周末(周一至周五)的天数 [英] Calculating days to excluding weekends (Monday to Friday) in SQL Server

问题描述

如何计算 SQL Server 2008 中表(从第一行到最后)的两个日期之间的工作日数?

How can I calculate the number of work days between two dates from table (from the 1st row to the end) in SQL Server 2008?

我试过这样的东西，但它不起作用

I tried something like this, but it does not work

DECLARE @StartDate as DATETIME, @EndDate as DATETIME

Select @StartDate = date2 from testtable ;
select @EndDate = date1 from testtable ;

SELECT
   (DATEDIFF(dd, @StartDate, @EndDate) + 1)
  -(DATEDIFF(wk, @StartDate, @EndDate) * 2)
  -(CASE WHEN DATENAME(dw, @StartDate) = 'Sunday' THEN 1 ELSE 0 END)
  -(CASE WHEN DATENAME(dw, @EndDate) = 'Saturday' THEN 1 ELSE 0 END)

推荐答案

我总是推荐 日历表，那么你可以简单地使用:

I would always recommend a Calendar table, then you can simply use:

SELECT  COUNT(*)
FROM    dbo.CalendarTable
WHERE   IsWorkingDay = 1
AND     [Date] > @StartDate
AND     [Date] <= @EndDate;

由于 SQL 不了解国定假日，例如，两个日期之间的工作日数并不总是代表工作日数.这就是为什么大多数数据库都必须使用日历表的原因.它们不占用大量内存并简化了大量查询.

Since SQL has no knowledge of national holidays for example the number of weekdays between two dates does not always represent the number of working days. This is why a calendar table is a must for most databases. They do not take a lot of memory and simplify a lot of queries.

但如果这不是一个选项，那么您可以相对轻松地动态生成日期表并使用它

But if this is not an option then you can generate a table of dates relatively easily on the fly and use this

SET DATEFIRST 1;
DECLARE @StartDate DATETIME = '20131103', 
        @EndDate DATETIME = '20131104';

-- GENERATE A LIST OF ALL DATES BETWEEN THE START DATE AND THE END DATE
WITH AllDates AS
(   SELECT  TOP (DATEDIFF(DAY, @StartDate, @EndDate))
            D = DATEADD(DAY, ROW_NUMBER() OVER(ORDER BY a.Object_ID), @StartDate)
    FROM    sys.all_objects a
            CROSS JOIN sys.all_objects b
)
SELECT  WeekDays = COUNT(*)
FROM    AllDates
WHERE   DATEPART(WEEKDAY, D) NOT IN (6, 7);

<小时>

编辑

如果您需要计算两个日期列之间的差异，您仍然可以像这样使用日历表:

If you need to calculate the difference between two date columns you can still use your calendar table as so:

SELECT  t.ID,
        t.Date1,
        t.Date2,
        WorkingDays = COUNT(c.DateKey)
FROM    TestTable t
        LEFT JOIN dbo.Calendar c
            ON c.DateKey >= t.Date1
            AND c.DateKey < t.Date2
            AND c.IsWorkingDay = 1
GROUP BY t.ID, t.Date1, t.Date2;

SQL-Fiddle 示例

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