正则表达式去除尾随零 [英] Regex for removing trailing zeros

问题描述

我要寻找一个正规的前pression（.NET）删除尾随零：

11645766.560000001000  - > 11645766.560000001
10190045.740000000000  - > 10190045.74
1455720.820000000100  - > 1455720.8200000001 

等等...

---

我使用正则表达式，在String.Trim（），因为该数字是在一个字符串，实际的例子：

  BEGIN＆GT;！＆GT; C85.18 POS_LEVEL.T129 {11645766.560000001000} = POS_LEVEL.T129 {10190045.740000000000} + WORK_LEVEL.T129 {1455720.820000000100} END;
 

需要转换为：

  BEGIN＆GT;！＆GT; C85.18 POS_LEVEL.T129 {11645766.560000001} = POS_LEVEL.T129 {10190045.74} + WORK_LEVEL.T129 {1455720.8200000001} END;
 

解决方案

如果该数字被嵌入在一个随机字符串，正则表达式是要走的路：

替换 （小于？。？= \ \ D +）（？= \ D | $）0 + 有一个空字符串

这将削减尾随零，如果他们在一段时间处于小数后出现（它会永远留下一个零）。它也占出现在最后的号码。

既然你已经添加在此期间，.NET标签，这里的code：

 字符串替换= Regex.Replace（
                         inputString，
                         @（？。？＆LT; = \ \ D +）0 +（？= \ D | $），
                         的String.Empty）;
 

I am looking for a regular expression (.NET) to remove trailing zeros:

11645766.560000001000   ->  11645766.560000001
10190045.740000000000   ->  10190045.74
1455720.820000000100    ->  1455720.8200000001  

etc...

---

I am using regex, over String.Trim(), because the numbers are in one string, actual example:

!BEGIN !>>C85.18 POS_LEVEL.T129{11645766.560000001000} = POS_LEVEL.T129 {10190045.740000000000} + WORK_LEVEL.T129{1455720.820000000100} END;

need to convert to:

!BEGIN !>>C85.18 POS_LEVEL.T129{11645766.560000001} = POS_LEVEL.T129{10190045.74} + WORK_LEVEL.T129{1455720.8200000001} END;

解决方案

If the numbers are embedded in a random string, regexes are the way to go:

Replace (?<=\.\d+?)0+(?=\D|$) with an empty string

That will trim trailing zeros if they appear after the period in a decimal number (it will always leave a single zero). It also accounts for numbers that appear at the very end.

And since you've added the .NET tag in the meantime, here's the code:

string replaced = Regex.Replace(
                         inputString,
                         @"(?<=\.\d+?)0+(?=\D|$)",
                         String.Empty);

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