删除 SQL 中的每个交替行 [英] Delete Every Alternate Row in SQL

问题描述

我需要清理一个包含三列的表，ID(唯一标识符)、观察(nvarchar)和时间戳(datetimeoffset).内容由两个传感器以 1 小时间隔生成，两个传感器的 Observation 值相同.我的想法是做一个 SELECT 查询，例如

I need to clean up a table which has three columns, ID (uniqueidentifier), Observation (nvarchar), and Timestamp (datetimeoffset). The content is generated by two sensors at 1 hour interval, and the value of Observation is the same from the two sensors. My idea is to do a SELECT query such as

SELECT * FROM [Records] ORDER BY [Timestamp]

然后删除每一行.

我在 SO 如何删除每个备用行上找到了这个在访问表中，但在这里并不真正适用，因为 ID 不是 Int 而是 UID.

I found this on SO how to delete every alternate row in access table, but doesn't really applies here as the ID is not Int but UID.

数据示例如下:

推荐答案

如果您使用的是 SQL Server 2005 或更高版本，您可以执行类似的操作.

If you are on SQL Server 2005 or later you can do something like this.

delete T
from (
       select row_number() over(order by [Timestamp]) as rn
       from YourTable
       where SomeColumn = @SomeValue
     ) T
where T.rn % 2 = 0

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