排序其值的最后几个字符数组？ [英] Sort an array by the last couple characters of its values?

问题描述

在PHP中，如何也许有排序近一其价值观的字符数组？举个例子，下面的数组：

In PHP, how might one sort an array by the last couple of characters of its values? Take, for example, the following array:

$donuts[0] = "Chocolate 02";
$donuts[1] = "Jelly 16";
$donuts[2] = "Glazed 01";
$donuts[3] = "Frosted 12";

排序后，数组应该是这样的（注意根据各值的最后两个字符的顺序......也注意到重写的指标）：

After the sort, the array would look like this (note the order based on the last two characters of each value... also note the rewritten indexes):

$donuts[0] = "Glazed 01";
$donuts[1] = "Chocolate 02";
$donuts[2] = "Frosted 12";
$donuts[3] = "Jelly 16";

我似乎无法找到一个内置的功能，可以做到这一点，并已货架我的大脑得到这个成就的最简单，最有效的方式。帮帮我！和感谢！

I can't seem to find a built-in function that can do this and have been racking my brain for the simplest and most efficient way to get this accomplished. Help! And thanks!

推荐答案

这应该做的伎俩：

header('Content-Type: Text/Plain');
$donuts[0] = "Chocolate 02";
$donuts[1] = "Jelly 16";
$donuts[2] = "Glazed 01";
$donuts[3] = "Frosted 12";

print_r($donuts);

usort($donuts, function ($a, $b){
    return substr($b, -2) - substr($a, -2);
});

print_r($donuts);

注意

1. 要转换从最高到最小：

1. To convert from highest to smallest:

return substr($b, -2) - substr($a, -2);

这答案做一个假设，最后2个字符被使用。

This answer make an assumption that the last 2 characters is to be used.

更新

要让它在PHP 5.2版本中，将收益部分工作：

To make it work on PHP version 5.2, change the return part to:

return substr($b, strlen($b) - 2) - substr($a, strlen($a) - 2);

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