使用pivot将多个值显示到sql server中的列中 [英] Displaying multiple values into columns in sql server using pivot
本文介绍了使用pivot将多个值显示到sql server中的列中的处理方法,对大家解决问题具有一定的参考价值,需要的朋友们下面随着小编来一起学习吧!
问题描述
declare @t table
(
driver varchar(20),
roadband varchar(20),
category varchar(20),
points int
)
INSERT INTO @T VALUES( 'Dan' ,'20 Mph','CAT1',58)
INSERT INTO @T VALUES( 'Dan' ,'20 Mph', 'CAT2', 0)
INSERT INTO @T VALUES( 'Dan' ,'20 Mph', 'CAT3', 0)
INSERT INTO @T VALUES( 'Dan' ,'30 Mph', 'CAT1', 102)
INSERT INTO @T VALUES( 'Dan' ,'30 Mph', 'CAT2', 30)
INSERT INTO @T VALUES( 'Dan' ,'30 Mph', 'CAT3', 0)
INSERT INTO @T VALUES( 'Dan' ,'40 Mph', 'CAT1', 6)
INSERT INTO @T VALUES( 'Dan' ,'40 Mph', 'CAT2', 3)
INSERT INTO @T VALUES( 'Dan' ,'40 Mph', 'CAT3', 0)
INSERT INTO @T VALUES( 'Dan' ,'50 Mph', 'CAT1', 5)
INSERT INTO @T VALUES( 'Dan' ,'50 Mph', 'CAT2', 0)
INSERT INTO @T VALUES( 'Dan' ,'50 Mph', 'CAT3', 0)
INSERT INTO @T VALUES( 'Dan' ,'60 Mph', 'CAT1', 0)
INSERT INTO @T VALUES( 'Dan' ,'60 Mph', 'CAT2', 0)
INSERT INTO @T VALUES( 'Dan' ,'60 Mph', 'CAT3', 0)
INSERT INTO @T VALUES( 'Dan' ,'70 Mph', 'CAT1', 0)
INSERT INTO @T VALUES( 'Dan' ,'70 Mph', 'CAT2', 0)
INSERT INTO @T VALUES( 'Dan' ,'70 Mph', 'CAT3', 0)
INSERT INTO @T VALUES( 'John' ,'20 Mph', 'CAT1', 6)
INSERT INTO @T VALUES( 'John' ,'20 Mph', 'CAT2', 0)
INSERT INTO @T VALUES( 'John' ,'20 Mph', 'CAT3', 0)
INSERT INTO @T VALUES( 'John' ,'30 Mph', 'CAT1', 1228)
INSERT INTO @T VALUES( 'John' ,'30 Mph', 'CAT2', 654)
INSERT INTO @T VALUES( 'John' ,'30 Mph', 'CAT3', 0)
INSERT INTO @T VALUES( 'John' ,'40 Mph', 'CAT1', 196)
INSERT INTO @T VALUES( 'John' ,'40 Mph', 'CAT2', 117)
INSERT INTO @T VALUES( 'John' ,'40 Mph', 'CAT3', 0)
INSERT INTO @T VALUES( 'John' ,'50 Mph', 'CAT1', 6)
INSERT INTO @T VALUES( 'John' ,'50 Mph', 'CAT2', 14)
INSERT INTO @T VALUES( 'John' ,'50 Mph', 'CAT3', 0)
INSERT INTO @T VALUES( 'John' ,'60 Mph', 'CAT1', 0)
INSERT INTO @T VALUES( 'John' ,'60 Mph', 'CAT2', 0)
INSERT INTO @T VALUES( 'John' ,'60 Mph', 'CAT3', 0)
INSERT INTO @T VALUES( 'John' ,'70 Mph', 'CAT1', 0)
INSERT INTO @T VALUES( 'John' ,'70 Mph', 'CAT2', 0)
INSERT INTO @T VALUES( 'John' ,'70 Mph', 'CAT3', 0)
我需要以 Roadband
和 Category
为中心..
I need to pivot on Roadband
and Category
..
我已经写了查询..需要一些帮助..
I have written the query .. need some help..
select * from
(
select
Driver, ROADBAND, category,SUM(points) as Points
from @t
where DRIVER is not null
group by DRIVER ,ROADBAND,CATEGORY
) main
pivot
(
sum(Points)
for ROADBAND in ([20 Mph],[30 Mph],[40 Mph],[50 Mph],[60 Mph],[70 Mph])
) pq
现在如何通过路带为每个类别制作支点.
Now how can make the pivot for each category by roadband.
请帮忙.
推荐答案
根据您的问题,我不确定您想要列中的值以及行中的值,因此我编写了两个查询,希望其中一个可以回答您的问题问题:
From your question I wasn't sure what values you wanted in columns and what should be in rows so I wrote both queries, I hope one of them answers your question:
SELECT *
FROM (
SELECT category
, roadband
, SUM(points) points_per_category_roadband
FROM @t
GROUP BY
category, roadband
) tbl
PIVOT
(
SUM(points_per_category_roadband) FOR roadband IN ([20 Mph],[30 Mph],[40 Mph],[50 Mph],[60 Mph],[70 Mph])
) pvt
SELECT *
FROM (
SELECT roadband
, category
, SUM(points) points_per_category_roadband
FROM @t
GROUP BY
roadband, category
) tbl
PIVOT
(
SUM(points_per_category_roadband) FOR category IN ([CAT1],[CAT2],[CAT3])
) pvt
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