计算加班时间的新列 [英] new column to calculate overtime

问题描述

我编写并管理了这个查询，以通过 dateDiff 函数计算一个人每天工作的总时间，现在我被困在一个地方.我想计算一下，如果一个人随着时间的推移完成了比新列应该在 hh:mm 中显示 OVERITME.

I wrote and managed this query to calculate total time a person has worked per day by dateDiff function now i am stuck at one place. i want to calculate that if a person has done over time than a new column should show OVERITME in hh:mm.

在我们办公室的总工作时间为 08:00 小时，超过 8 小时被视为加班，例如如果一个人在 08:35 工作，那么一栏应该显示一个人在 00:35 工作

I n our office total working hours are 08:00 hours, greater than 8 hours are considered overtime so e.g. if a person has worked 08:35 hours than a column should show that a person has worked 00:35

查询:

with times as (
SELECT    t1.EmplID
        , t3.EmplName
        , min(t1.RecTime) AS InTime
        , max(t2.RecTime) AS [TimeOut]
        , t1.RecDate AS [DateVisited]
FROM  AtdRecord t1 
INNER JOIN 
      AtdRecord t2 
ON    t1.EmplID = t2.EmplID 
AND   t1.RecDate = t2.RecDate
AND   t1.RecTime < t2.RecTime
inner join 
      HrEmployee t3 
ON    t3.EmplID = t1.EmplID 
group by 
          t1.EmplID
        , t3.EmplName
        , t1.RecDate
)
SELECT EmplID
                ,EmplName
                ,InTime
                ,[TimeOut]
                ,[DateVisited]
                ,CASE 
                    WHEN minpart = 0
                        THEN CAST(hourpart AS NVARCHAR(200)) + ':00'
                    WHEN minpart <10
                        THEN CAST(hourpart AS NVARCHAR(200)) + ':0'+ CAST(minpart AS NVARCHAR(200))
                    ELSE CAST(hourpart AS NVARCHAR(200)) + ':' + CAST(minpart AS NVARCHAR(200))

END AS 'total time'
            FROM (
                SELECT EmplID
                    ,EmplName
                    ,InTime
                    ,[TimeOut]
                    ,[DateVisited]
                    ,DATEDIFF(minute, InTime, [TimeOut])/60 AS hourpart
                    ,DATEDIFF(minute, InTime, [TimeOut]) % 60 AS minpart
                FROM times
                ) source

输出:

推荐答案

试试这个:

with times as (
SELECT    t1.EmplID
        , t3.EmplName
        , min(t1.RecTime) AS InTime
        , max(t2.RecTime) AS [TimeOut]
        , cast(min(t1.RecTime) as datetime) AS InTimeSub
        , cast(max(t2.RecTime) as datetime) AS TimeOutSub
        , t1.RecDate AS [DateVisited]
FROM  AtdRecord t1 
INNER JOIN 
      AtdRecord t2 
ON    t1.EmplID = t2.EmplID 
AND   t1.RecDate = t2.RecDate
AND   t1.RecTime < t2.RecTime
inner join 
      HrEmployee t3 
ON    t3.EmplID = t1.EmplID 
group by 
          t1.EmplID
        , t3.EmplName
        , t1.RecDate
)
SELECT EmplID
,EmplName
,InTime
,[TimeOut]
,[DateVisited]
,convert(char(5),cast([TimeOutSub] - InTimeSub as time), 108) totaltime
,convert(char(5), case when TimeOutSub - InTimeSub >= '08:01' then 
cast(TimeOutSub - dateadd(hour, 8, InTimeSub) as time) else '00:00' end, 108) as overtime
FROM times

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