PHP：从阵列中两个最近的邻居？ [英] PHP: Get two nearest neighbors from array?

问题描述

我发现<一个href=\"http://stackoverflow.com/questions/4032753/picking-the-nearest-value-from-an-array-reflecting-ranges\">this螺纹有关从基于已知值的数组挑选最接近/最接近的值。那么如果一个人想挑两个最近从阵列中寻找相同的值说呢？

  $回扣=阵列（
   1 =＆GT; 0，
   3 =＆GT; 10，
   5 =＆GT; 25，
  10 =＆GT; 35）
 

解决方案

  $回扣=阵列（
   1 =＆GT; 0，
   3 =＆GT; 10，
   5 =＆GT; 25，
  10 =＆GT; 35）;
功能getArrayNeighborsByKey（$数组$ findKey）{    如果（！array_key_exists（$阵列，$ findKey））{
        返回FALSE;
    }    $选择= $prevous = $下一= NULL;    的foreach（$数组$关键=＆GT; $值）{
        $ thisValue =阵列（$关键=＆GT; $值）;
        如果（$关键=== $ findKey）{
           $选择= $ thisValue;
           继续;
        }
        如果（$选择！== NULL）{
            接下来$ = $ thisValue;
            打破;
        }
        $previous = $ thisValue;    }   返回阵列（
            'preV =＆GT; $previous，
            当前= GT; $选择，
            '下一个'=＆GT;接下来$
    ）;}
 

看看吧！

I found this thread about picking the closest/nearest value from an array based upon a known value. What about if one wants to pick the two nearest values from an array looking at the same say?

$rebates = array(
   1 => 0,
   3 => 10,
   5 => 25,
  10 => 35)

解决方案

$rebates = array(
   1 => 0,
   3 => 10,
   5 => 25,
  10 => 35);


function getArrayNeighborsByKey($array, $findKey) {

    if ( ! array_key_exists($array, $findKey)) {
        return FALSE;
    }

    $select = $prevous = $next = NULL;

    foreach($array as $key => $value) {
        $thisValue = array($key => $value);
        if ($key === $findKey) {
           $select = $thisValue;
           continue;
        }
        if ($select !== NULL) {
            $next = $thisValue;
            break;
        }
        $previous = $thisValue;

    }

   return array(
            'prev' => $previous,
            'current' => $select,
            'next' => $next
    );

}

See it!

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