需要写一个C程序来删除彼此相邻重复字符 [英] Need to write a C Program to remove repeated characters adjacent to each other

问题描述

我只需要去除重复字符是彼此相邻的。

例如：如果输入heeellooo wooorllldd，输出应该是HELO世界。我目前得到的输出是HELO WRD。

这是code，我有。

 的#include＆LT;＆stdio.h中GT;
＃包括LT＆;＆string.h中GT;主要（）
{
    烧焦海峡[] =heeello wooorld
    冗余（STR）;
}无效冗余（字符*海峡）
{
    INT检查= 0;
    INT I，J;
    焦炭CH;    而（STR [检查]）
    {
        CH = STR【检​​查】;
        I = J =检查+ 1;        而（STR [I]）
        {
            如果（STR由[i]！= CH）
            {
                海峡[J] = STR [I]
                J ++;
            }            我++;
        }        海峡[J] ='\\ 0';
        检查++;
    }    的printf（删除重复后的字符串：％S \\ n，STR）;
}
 

解决方案

我一直在寻找一个简约的解决方案。只是为了好玩。

 无效冗余（字符* STR）{
    INT lastch = -1; / *最后一次读取字符* /
    字符* INPP = str中; / *指针输入位置* /
    字符* OUTP = str中; / *指针输出位置* /
    而（* INPP！='\\ 0'）{
        如果（* INPP！= lastch）{
            * OUTP ++ = lastch = * INPP;
        }
        INPP ++;
    }
    * OUTP ='\\ 0';
    的printf（删除重复后的字符串：％S \\ n，STR）;
}
 

I need to remove only the repeated characters that are adjacent to each other.

Example: if the input is "heeellooo wooorllldd", the output should be "helo world". The output I am currently getting is "helo wrd".

This is the code i have.

#include <stdio.h>
#include <string.h>

main()
{
    char str[]="heeello wooorld";
    redundant(str);
}

void redundant(char *str)
{
    int check=0;
    int i,j;
    char ch;

    while(str[check]) 
    {
        ch = str[check];
        i = j = check + 1;

        while(str[i]) 
        {
            if(str[i] != ch) 
            {
                str[j] = str[i];
                j++; 
            }

            i++; 
        }

        str[j]='\0';
        check++;
    }

    printf("String after removing duplicates : %s\n",str);
} 

解决方案

I was looking for a minimalistic solution. Just for fun.

void redundant(char *str) {
    int lastch = -1;         /* last read character */
    char* inpp = str;        /* pointer to input location */
    char* outp = str;        /* pointer to output location */
    while (*inpp != '\0') {
        if (*inpp != lastch) {
            *outp++ = lastch = *inpp;
        }
        inpp++;
    }
    *outp = '\0';
    printf("String after removing duplicates : %s\n", str);
}  

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