传递数组作为参数在C一个新的线程 [英] Passing Array as argument to a new thread in C

问题描述

我试图数组作为参数传递给函数使用pthread_create的一个新的线程，这可能吗？我有一个整数数组，并且从创建线程方法调用一个计算平均的方法，但我似乎无法给我的数组正确地传递到方法。这里是我的code：
    INT NUMS [];

  INT平均水平;INT大小= 0;
无效* calcAvg为（int * NUMS []）;INT主（INT ARGC，CHAR *的argv []）{
    / *初始化整数数组传递* /
    NUMS [ARGC  -  1];
    的for（int i = 0; I＆LT; ARGC  -  1;我++）{
        NUMS [I] =的atoi（argv的[I + 1]）;
        大小++;
    }    / *线程标识符* /
    的pthread_t avgThread;    在pthread_create（安培; avgThread，NULL，calcAvg，NUMS）;    在pthread_join（avgThread，NULL）;    的printf（平均=％d个，平均）;
}无效* calcAvg为（int * NUMS []）{
    INT总和;
    的for（int i = 0; I＆LT;大小;我++）{
        总和+ = NUM​​S [I]
    }
    平均=总和/（大小）;
    了pthread_exit（0）;
}
 

解决方案

有大量的问题，在你的code，我修正了一些编译
希望这将有助于

编译：gcc的-o主要的main.c -lpthread

执行：./main 2 5

输出：3

 的#include＆LT; pthreads.h中＆GT;
＃包括LT＆;＆stdio.h中GT;
＃包括LT＆;＆stdlib.h中GT;INT平均水平;INT大小= 0;
无效* calcAvg（无效* ARG）;
INT主（INT ARGC，CHAR *的argv []）{
  / *初始化整数数组传递* /
  为int * NUMS =（INT *）malloc的（（ARGC  -  1）* sizeof的（INT））;
  INT I = 1;
  对于（i = 1; I＆LT; ARGC，我++）{
    NUMS [I-1] =与atoi（argv的[I]）;
    大小++;
  }  / *线程标识符* /
  的pthread_t avgThread;  在pthread_create（安培; avgThread，NULL，calcAvg，（无效*）NUMS）;  在pthread_join（avgThread，NULL）;
  的printf（平均=％d个\\ N，平均）;
  免费（NUMS）;}
无效* calcAvg（无效* ARG）{
  为int * val_p =（INT *）ARG;
  INT总和= 0;
  INT I = 0;
  对于（i = 0; I＆LT;大小;我++）{
    总和+ = val_p [I]
  }
  平均=总和/（大小）;
  了pthread_exit（0）;
}
 

I am attempting to pass an array as an argument to a function in a new thread using pthread_create, is this possible? I have an array of integers and a calculate average method that is called from the create thread method but I cannot seem to pass my array into the method correctly. Here is my code: int nums[];

int average;

int size = 0;


void *calcAvg(int *nums[]);

int main(int argc, char *argv[]){
    /* initialize an array of the integers to be passed */
    nums[argc - 1];
    for(int i = 0; i < argc - 1; i++){
        nums[i] = atoi(argv[i + 1]);
        size++;
    }

    /* Thread Identifier */
    pthread_t avgThread;

    pthread_create(&avgThread, NULL, calcAvg, nums);

    pthread_join(avgThread, NULL);

    printf("average= %d", average);
}

void *calcAvg(int *nums[]){
    int sum;
    for(int i = 0; i < size; i++){
        sum += nums[i];
    }
    average = sum / (size);
    pthread_exit(0);
}

解决方案

there is lots of problem in your code, i fix some to compile hope it will help

compile: gcc -o main main.c -lpthread

execute: ./main 2 5

output: 3

#include <pthread.h>
#include <stdio.h>
#include <stdlib.h>

int average;

int size = 0;


void *calcAvg(void *arg);
int main(int argc, char *argv[]){
  /* initialize an array of the integers to be passed */
  int *nums = (int*)malloc((argc - 1)*sizeof(int));
  int i = 1;
  for(i = 1; i < argc ; i++){
    nums[i-1] = atoi(argv[i]);
    size++;
  }

  /* Thread Identifier */
  pthread_t avgThread;

  pthread_create(&avgThread, NULL, calcAvg, (void*)nums);

  pthread_join(avgThread, NULL);
  printf("average = %d \n",average);
  free(nums);

}
void *calcAvg(void *arg){
  int *val_p = (int *) arg;
  int sum = 0;
  int i = 0;
  for( i = 0; i < size; i++){
    sum += val_p[i];
  }
  average = sum / (size);
  pthread_exit(0);
}

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