使用 XSLT 过滤 XML 标签 [英] filtering XML tags using XSLT

问题描述

我有以下 XML 代码.

I have the following XML code.

您会注意到标签说明重复了，但具有不同的属性.

You will notice the tag Description is repeated, but with different attributes.

我正在使用 XSLT 尝试删除具有启用属性的描述标记.

I am using XSLT to try and remove the Description tag with the enabled attribute.

<Batch>
- <Promotion>
  <LastUpdated>2008-01-22T11:58:05+00:00</LastUpdated> 
  <MajorVersion>1</MajorVersion> 
  <MinorVersion>29</MinorVersion> 
  <PromotionID>000873</PromotionID> 
  <Description enabled="1">*P* Free Mistletoe</Description> 
  <Description country="GB" language="en" variant="">WANTED LINE 1</Description>
 </Promotion>
 <Promotion>
   <LastUpdated>2008-01-22T11:58:05+00:00</LastUpdated> 
   <MajorVersion>1</MajorVersion> 
   <MinorVersion>29</MinorVersion> 
   <PromotionID>000874</PromotionID> 
   <Description enabled="1">*P* Free Mistletoe</Description> 
   <Description country="GB" language="en" variant="">WANTED LINE 2</Description>
 </Promotion> 
</batch>

这就是我想要达到的，还有其他标签，它是删除一个基于我正在尝试解析的属性的行.

This is what I am trying to get to, there are other tags, it is the removal of one line based on an attribute I am trying to resolve.

- <promotions>
-   <promotion>
      <promotionID>000873</promotionID> 
      <description country="GB" language="en" variant="">WANTED LINE 1</description>
    </promotion>
-   <promotion> 
      <promotionID>000874</promotionID> 
      <description country="GB" language="en" variant="">WANTED LINE 2</description>
    </promotion> 
  </promotions>

我使用的 XSLT 代码是

The XSLT code I am using is

<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform">
<xsl:output method="xml" indent="yes"/>

<xsl:template match="node()|@*">
  <xsl:copy>
  <xsl:apply-templates select="node()|@*"/>
  </xsl:copy>
</xsl:template>
<xsl:template match="//promotion/Description[@country='GB']"/> 
<xsl:template match="/"> 

<promotions> 
<xsl:for-each select="Batch/Promotion">  
  <promotion>
    <promotion_id><xsl:value-of select="PromotionID"/></promotion_id>    
    <description><xsl:value-of select="Description"/></description>
  </promotion>
</xsl:for-each>   
</promotions>   
</xsl:template>
</xsl:stylesheet> 

如果有人能指出我正确的方向，我将不胜感激.

If anyone could point me in the right direction I would be very grateful.

保罗

推荐答案

一般来说，为了移除一个元素，你必须指定一个没有任何内容的模板.就您而言，这可能是:

Generally, in order to remove an element, you have to specify a template without any contents. In your case, this could be:

<xsl:template match="/Batch/Promotion/Description[@enabled = '1']"/>

然而，在您的 XSLT 代码中，您需要构建自己的 <description> 元素的特殊情况.为了准确获得所需 元素的值，请在 元素中选择它:

In your XSLT code, however, you have the somewhat special case of constructing your own <description> element. In order to get exactly the value of the desired <Description> element, select it in your <xsl:value-of> element:

<description><xsl:value-of select="Description[@country = 'GB']"/></description>

这就是您在问题中所描述的，但是您的预期结果代码意味着您已经想要复制 元素的属性?在这种情况下，我会使用 <xsl:copy-of>:

This is what you have described in your question, however your expected result code implies that you already want to copy the attributes of the <Description> element? In that case, I'd go for this solution with <xsl:copy-of>:

<description><xsl:copy-of select="Description[@country = 'GB']/node()|Description[@country = 'GB']/@*"/></description>

它复制 元素(node())的全部内容，以及它的任何属性(@*)代码>).

It copies the whole contents of the <Description> element (node()), as well as any of its attributes (@*).

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