检查部分匹配阵列(PHP) [英] Check array for partial match (PHP)
问题描述
我有文件名的数组,我需要核对一个code,例如:
阵列(120_120_435645.jpg,150_150_312312.jpg,250_250_1232327.jpg);
字符串为312312,所以因为它包含字符串的话将匹配150_150_312312.jpg。
如果有在搜索中的所有没有匹配然后标记的code为失踪人。
我试过in_array但如果它是完全匹配,这似乎任何返回true,不知道是不是array_filter将做到这一点枯萎......
任何意见谢谢...也许是我一直盯着它太长,咖啡可以帮助:)
$文件名=阵列(120_120_435645.jpg,150_150_312312.jpg,250_250_1232327.jpg);
$匹配= preg_grep(/ 312312 /,$文件名);
的print_r($比赛);
输出:
阵列
(
[1] => 150_150_312312.jpg
)
或者,如果你不想使用正则表达式,你可以简单地使用 strpos
如提出这个回答:
的foreach($文件名作为文件名$){
如果(strpos($文件名,'312312')!== FALSE){
回声真;
}
}
I have an array of filenames which I need to check against a code, for example
array("120_120_435645.jpg","150_150_312312.jpg","250_250_1232327.jpg");
the string is "312312" so it would match "150_150_312312.jpg" as it contains that string. If there are no matches at all within the search then flag the code as missing.
I tried in_array but this seems to any return true if it is an exact match, don't know if array_filter will do it wither...
Thanks for any advice...perhaps I have been staring at it too long and a coffee may help :)
$filenames = array("120_120_435645.jpg","150_150_312312.jpg","250_250_1232327.jpg");
$matches = preg_grep("/312312/", $filenames);
print_r($matches);
Output:
Array
(
[1] => 150_150_312312.jpg
)
Or, if you don't want to use regex, you can simply use strpos
as suggested in this answer:
foreach ($filenames as $filename) {
if (strpos($filename,'312312') !== false) {
echo 'True';
}
}
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