从打字稿中的非静态函数访问静态成员 [英] accessing static member from non-static function in typescript

问题描述

我正在尝试从类中的非静态函数访问静态成员，但收到一条错误消息

I am trying to access a static member from a non-static function in the class, and I get an error saying

不能通过实例变量访问静态成员

Static member cannot be accessed off an instance variable

这是我的代码的样子 -

this is how my code looks -

class myClass {
  public static testStatic: number = 0;
  public increment(): void {
    this.testStatic++;
  }
}

根据我对静态成员/方法的理解，我们不应该访问静态函数中的非静态成员，但反之亦然.静态成员已经创建并且有效，为什么我不能从我的非静态方法访问?

From what I understand of static members/methods, we shouldn't access non-static members in static functions, but vice-versa should be possible. the static member is already created and is valid, so why can't I access from my non-static method?

推荐答案

从类内部访问静态成员的方式与从类外部相同:

Access static members from inside the class the same way you would from outside the class:

class myClass {
  public static testStatic: number = 0;
  public increment(): void {
    myClass.testStatic++;
  }
}

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