使用 proc_open() 进行多输入 [英] Multiple input with proc_open()

问题描述

我目前正在开发一个在线程序.我正在编写一个 php 脚本，它在命令行中使用 proc_open() (在 Linux Ubuntu 下)执行命令.到目前为止，这是我的代码:

I'm currently working on an online program. I'm writing a php script that executes a command in the command line with proc_open() (under Linux Ubuntu). This is my code so far:

<?php
$cmd = "./power";

$descriptorspec = array(
   0 => array("pipe", "r"),
   1 => array("pipe", "w"),
   2 => array("pipe", "w"),
);

$process = proc_open($cmd, $descriptorspec, $pipes);

if (is_resource($process)) {

    fwrite($pipes[0], "4");
    fwrite($pipes[0], "5");
    fclose($pipes[0]);

    while($pdf_content = fgets($pipes[1]))
    {
        echo $pdf_content . "<br>";
    }
    fclose($pipes[1]);

    $return_value = proc_close($process);
}
?>

power 是一个要求输入 2 次的程序(它需要一个底数和一个指数并计算底数 ^ 指数).它是用汇编写的.但是当我运行这个脚本时，我得到了错误的输出.我的输出是1"，但我希望输出 4^5.

power is a program that asks for input 2 times (it takes a base and an exponent and calculates base ^ exponent). It's written in Assembly. But when I run this script, I get wrong output. My output is "1" but I expect 4^5 as output.

当我运行一个接受一个输入的程序时，它可以工作(我测试了一个简单的程序，该程序将输入的值增加一).

When I Run a program that takes one input, it works (I've tested an easy program that increments the entered value by one).

我想我遗漏了一些关于 fwrite 命令的内容.有人可以帮我吗?

I think I'm missing something regarding the fwrite command. Could anyone please help me?

提前致谢！

推荐答案

你忘记给管道写一个换行符，所以你的程序会认为它只有 45 作为输入.试试这个:

You forgot to write a newline to the pipe, so your program will think that it got only 45 as input. Try this:

fwrite($pipes[0], "4");
fwrite($pipes[0], "\n");
fwrite($pipes[0], "5");
fclose($pipes[0]);

或更短:

fwrite($pipes[0], "4\n5");
fclose($pipes[0]);

这篇关于使用 proc_open() 进行多输入的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！