如何在两个多头转换为字节数组=如何UUID转换为字节数组? [英] How to convert two longs to a byte array = how to convert UUID to byte array?
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问题描述
我使用的Java类 UUID
,需要一个UUID转换为字节数组。奇怪的UUID类不提供toBytes()
方法。
I am using Javas UUID
and need to convert a UUID to a byte Array. Strangely the UUID Class does not provide a "toBytes()"
method.
我已经发现了这两种方法:
I already found out about the two methods:
UUID.getMostSignificantBits()
and
UUID.getLeasSignificantBits()
可是如何才能让成字节数组吗?结果应与拖车值一个byte []。不知何故,我需要做的Bitshifting但是,怎么样?
But how to get this into a byte array? the result should be a byte[] with those tow values. I somehow need to do Bitshifting but, how?
更新:
我发现:
ByteBuffer byteBuffer = MappedByteBuffer.allocate(2);
byteBuffer.putLong(uuid.getMostSignificantBits());
byteBuffer.putLong(uuid.getLeastSignificantBits());
这是方法corret?
Is this approach corret?
是否有任何其他的方法(用于学习目的)?
Are there any other methods (for learning purposes)?
非常感谢!
延斯
Thanks very much!! Jens
推荐答案
您可以使用的ByteBuffer
You can use ByteBuffer
byte[] bytes = new byte[16];
ByteBuffer bb = ByteBuffer.wrap(bytes);
bb.order(ByteOrder.LITTLE_ENDIAN or ByteOrder.BIG_ENDIAN);
bb.putLong(UUID.getMostSignificantBits());
bb.putLong(UUID.getLeastSignificantBits());
// to reverse
bb.flip();
UUID uuid = new UUID(bb.getLong(), bb.getLong());
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