如何将空格和逗号分隔的数字字符串转换为 int 列表? [英] How to convert a string of space- and comma- separated numbers into a list of int?
问题描述
我有一串数字,例如:
example_string = '0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11'
我想将其转换为列表:
example_list = [0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11]
我尝试了类似的东西:
for i in example_string:example_list.append(int(example_string[i]))
但这显然不起作用,因为字符串包含空格和逗号.但是,删除它们不是一种选择,因为像19"这样的数字会被转换为 1 和 9.你能帮我解决这个问题吗?
用逗号分割,然后映射到整数:
map(int, example_string.split(','))
或者使用列表推导式:
[int(s) for s in example_string.split(',')]
如果您想要列表结果,后者效果更好,或者您可以将 map()
调用包装在 list()
中.
这是可行的,因为 int()
容忍空格:
分割只是一个逗号也更能容忍变量输入;值之间使用 0、1 或 10 个空格都没有关系.
I have a string of numbers, something like:
example_string = '0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11'
I would like to convert this into a list:
example_list = [0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11]
I tried something like:
for i in example_string:
example_list.append(int(example_string[i]))
But this obviously does not work, as the string contains spaces and commas. However, removing them is not an option, as numbers like '19' would be converted to 1 and 9. Could you please help me with this?
Split on commas, then map to integers:
map(int, example_string.split(','))
Or use a list comprehension:
[int(s) for s in example_string.split(',')]
The latter works better if you want a list result, or you can wrap the map()
call in list()
.
This works because int()
tolerates whitespace:
>>> example_string = '0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11'
>>> list(map(int, example_string.split(','))) # Python 3, in Python 2 the list() call is redundant
[0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11]
>>> [int(s) for s in example_string.split(',')]
[0, 0, 0, 11, 0, 0, 0, 0, 0, 19, 0, 9, 0, 0, 0, 0, 0, 0, 11]
Splitting on just a comma also is more tolerant of variable input; it doesn't matter if 0, 1 or 10 spaces are used between values.
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