Swift 3:转换以 null 结尾的 UnsafePointer<UInt8>到一个字符串 [英] Swift 3: convert a null-terminated UnsafePointer<UInt8> to a string
问题描述
我有一个 ac api,它返回一个空终止的字符串,它是一个 unsigned char*
类型的数组(对应于 UnsafePointer
).
I have a c api that returns a null terminated string that is an array of type unsigned char*
(which would correspond to UnsafePointer<UInt8>
).
Swift 有初始化器 String(validatingUTF8:)
,但参数必须是 UnsafePointer
(又名 UnsafePointer
),并且没有简单的方法可以在两者之间进行转换.
Swift has the initializer String(validatingUTF8:)
, but the argument has to be UnsafePointer<CChar>
(a.k.a. UnsafePointer<Int8>
), and there is no trivial way to convert between the two.
如何将这个以空字符结尾的 c 字符串转换为 Swift 字符串?
How do I convert from this null-terminated c-string to a Swift string?
推荐答案
在 Swift 3 中,String
有两个初始化器
In Swift 3, String
has two initializers
public init(cString: UnsafePointer<CChar>)
public init(cString: UnsafePointer<UInt8>)
因此它可以从有符号和无符号字符的(以空字符结尾的)序列创建.所以
therefore it can be created from (null-terminated) sequences of both signed and unsigned characters. So
let s = String(cString: yourCharPointer)
应该可以正常工作.
String
有另一个初始化器
public init?(validatingUTF8 cString: UnsafePointer<CChar>)
which fails 在格式错误的 UTF-8 序列上而不是替换它们通过替换字符.这个 init 方法没有对应的取无符号字符.
which fails on ill-formed UTF-8 sequences instead of replacing them by the replacement characters. This init method has no counterpart taking unsigned characters.
采用 CString.swift中的现有实现a> 作为例子,添加这个作为扩展并不太难:
Taking the existing implementations in CString.swift as examples, it is not too difficult to add this as an extension:
extension String {
public init?(validatingUTF8 cString: UnsafePointer<UInt8>) {
guard let (s, _) = String.decodeCString(cString, as: UTF8.self,
repairingInvalidCodeUnits: false) else {
return nil
}
self = s
}
}
然后
if let s = String(validatingUTF8: yourCharPointer) {
print(s)
} else {
print("invalid UTF-8")
}
也适用于有符号和无符号字符的(以空字符结尾的)序列.
also works with (null-terminated) sequences of both signed and unsigned characters.
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