将输出格式化为表格 [英] Formatting output as table

问题描述

示例输入:

[('b', 'c', 4),('l', 'r', 5),('i', 'a', 6),('c', 't', 7),('a', '$', 8),('n', '$', 9)]

[0] 包含垂直标题，[1] 包含水平标题.

示例输出:

 cr a t $ $乙 4升 5我 67一个 89

注意:给定足够多的元组，可以填充整个表格:P

如何使用 [最好] 一行代码在 Python 中将输出格式化为表格?

解决方案

这是您修改后的问题的答案:

data = [['A','a','1'],['B','b','2'],['C','c','3'],['D','d','4']]# 期望输出:##   A B C D# 1# b 2# c 3# d 4# 检查数据由 colname, rowname, value 三元组组成assert all([3 == len(row) for row in data])# 将所有数据转换为字符串数据 = [ [str(c) for c in r] for r in data]# 检查所有数据是否为一个字符宽assert all([1 == len(s) for s in r for r in data])#==============================================================================# 详细版本#==============================================================================col_names, row_names, values = zip(*data) # 转置header_line = ' ' + ' '.join(col_names)row_lines = []对于 idx, (row_name, value) in enumerate(zip(row_names,values)):# 使用 ' '*n 得到 2n 个连续的空格.row_line = row_name + ' ' + ' '*idx + valuerow_lines.append(row_line)打印 header_line对于 row_lines 中的 r:打印 (r)

或者，如果这对你来说太长了，试试这个:

cs, rs, vs = zip(*data)print ('\n'.join([' '+' '.join(cs)] + [r+' '+' '*i+v for i,(r,v) in enumerate(zip(rs,vs))]))

两者都有以下输出:

 A B C D1乙 234

<小时>

这是您想要的核心内容(没有读者行或标题列)

<预><代码>>>>print('\n'.join([ ''.join([str(i+j+2).rjust(3)for i in range(10)]) for j in range(10) ]))2 3 4 5 6 7 8 9 10 113 4 5 6 7 8 9 10 11 124 5 6 7 8 9 10 11 12 135 6 7 8 9 10 11 12 13 146 7 8 9 10 11 12 13 14 157 8 9 10 11 12 13 14 15 168 9 10 11 12 13 14 15 16 179 10 11 12 13 14 15 16 17 1810 11 12 13 14 15 16 17 18 1911 12 13 14 15 16 17 18 19 20

它使用对 i 和 j 的嵌套列表理解来生成数字 i+j，然后 str.rjust() 将所有字段的长度填充为三个字符，最后使用 str.join() 将所有子字符串放在一起.

Example input:

[('b', 'c', 4),
('l', 'r', 5),
('i', 'a', 6),
('c', 't', 7),
('a', '$', 8),
('n', '$', 9)]

[0] contains the vertical heading, [1] contains the horizontal heading.

Example output:

  c r a t $ $
b 4  
l   5
i     6
c       7
a         8
n           9

Note: given enough tuples the entire table could be filled :P

How do I format output as a table in Python using [preferably] one line of code?

解决方案

Here's an answer for your revised question:

data = [
    ['A','a','1'],
    ['B','b','2'],
    ['C','c','3'],
    ['D','d','4']
]

# Desired output:
#
#   A B C D
# a 1
# b   2
# c     3
# d       4

# Check data consists of colname, rowname, value triples
assert all([3 == len(row) for row in data])
# Convert all data to strings
data = [ [str(c) for c in r] for r in data]
# Check all data is one character wide
assert all([1 == len(s) for s in r for r in data])

#============================================================================
# Verbose version
#============================================================================
col_names, row_names, values = zip(*data) # Transpose

header_line = '  ' + ' '.join(col_names)
row_lines = []
for idx, (row_name, value) in enumerate(zip(row_names,values)):
    # Use '  '*n to get 2n consecutive spaces.
    row_line = row_name + ' ' + '  '*idx + value
    row_lines.append(row_line)

print header_line
for r in row_lines:
    print (r)

Or, if that's too long for you, try this:

cs, rs, vs = zip(*data)
print ('\n'.join(['  '+' '.join(cs)] + [r+' '+'  '*i+v for i,(r,v) in enumerate(zip(rs,vs))]))

Both have the following output:

  A B C D
a 1
b   2
c     3
d       4

---

Here's the kernel of what you want (no reader row or header column)

>>> print('\n'.join([ ''.join([str(i+j+2).rjust(3)
    for i in range(10)]) for j in range(10) ]))

  2  3  4  5  6  7  8  9 10 11
  3  4  5  6  7  8  9 10 11 12
  4  5  6  7  8  9 10 11 12 13
  5  6  7  8  9 10 11 12 13 14
  6  7  8  9 10 11 12 13 14 15
  7  8  9 10 11 12 13 14 15 16
  8  9 10 11 12 13 14 15 16 17
  9 10 11 12 13 14 15 16 17 18
 10 11 12 13 14 15 16 17 18 19
 11 12 13 14 15 16 17 18 19 20

It uses a nested list comprehension over i and j to generate the numbers i+j, then str.rjust() to pad all fields to three characters in length, and finally some str.join()s to put all the substrings together.

这篇关于将输出格式化为表格的文章就介绍到这了，希望我们推荐的答案对大家有所帮助，也希望大家多多支持IT屋！