将所有客户从 Stripe API 检索到一个列表中的最佳做法是什么 [英] What is the best practice to retrieve all customers from Stripe API into one list

问题描述

当调用 Stripe::Customer.all(:limit => 100) 时，每次调用限制为 100.我们的客户比这多得多，我想同时得到他们.我是否遗漏了什么，或者这只能通过编写一个简单的循环来检查 has_more 属性，然后进行新调用直到 has_more = false ?

When calling Stripe::Customer.all(:limit => 100) there is a limit of 100 per call. We have a lot more customers than that, and I would like to get them all at once. Am I missing something, or is this only possible by writing a naive loop that checks on the has_more attribute and then makes a new call until has_more = false?

推荐答案

你说得对，你必须用游标写一个简单的循环 根据条带文档:

You are right, you must write a naive loop with a cursor per the stripe docs:

可选

用于分页的游标.starting_after 是一个对象 ID，用于定义您在列表中的位置.例如，如果您发出一个列表请求并收到 100 个以 obj_foo 结尾的对象，那么您的后续调用可以包含 starting_after=obj_foo 以获取列表的下一页.

A cursor for use in pagination. starting_after is an object ID that defines your place in the list. For instance, if you make a list request and receive 100 objects, ending with obj_foo, your subsequent call can include starting_after=obj_foo in order to fetch the next page of the list.

这里有一个，以防有人需要快速复制粘贴.

Here's one in case anyone needs a quick copy-paste.

  def self.all_stripe_customers
    starting_after = nil
    customers = []
    loop do
      results = Stripe::Customer.list(limit: 100, starting_after: starting_after)
      break if results.data.length == 0
      customers = customers + results.data
      starting_after = results.data.last.id  
    end
    return customers
  end

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