strtok() - 分段错误 [英] strtok() - Segmentation Fault

问题描述

<块引用>

可能的重复:
strtok 给出分段错误

我尝试使用 strtok 函数将字符串拆分为多个标记，但在此示例中它返回一个 seg.故障错误.我哪里错了??

#include #include int main(int argc, char** argv){int i=0;char * string = "HI:HOW:ARE:YOU:?", *tmp;而(1){if(i==0) tmp=strtok(string,":");否则 tmp=strtok(NULL,":");if(tmp==NULL) 中断；printf("%s\n",tmp);我++;}返回 1；}

解决方案

更改

char * string = "HI:HOW:ARE:YOU:?"

为了

char string [] = "HI:HOW:ARE:YOU:?"

用 char string [] 你有一个数组，而 char * 你有一个指针.当你声明一个数组时，它会请求空间来分配你的字符串的大小.char * 字符串创建一个指向文字字符串的指针.

char *string 的问题在于不应更改该点，因为字符串文字通常存储在只读内存中，从而导致 未定义行为 33

(有关更多详细信息，请阅读此 https://www.securecoding.cert.org/confluence/display/seccode/STR30-C.+Do+not+attempt+to+modify+string+literals )>

因此，由于使用 strtok 修改了字符串的内容并将其分解为更小的字符串(标记)，因此您会遇到问题.

Possible Duplicate:
strtok giving Segmentation Fault

I try to use strtok function to split string in many tokens but in this example it returns me a seg. fault error. Where i'm in wrong??

#include <stdio.h>
#include <string.h>

int main(int argc, char** argv){
    int i=0;
    char * string = "HI:HOW:ARE:YOU:?", *tmp;

    while(1){
        if(i==0) tmp=strtok(string,":");
        else tmp=strtok(NULL,":");
        if(tmp==NULL) break;
        printf("%s\n",tmp);
        i++;
    }
    return 1;
}

解决方案

Change

char * string = "HI:HOW:ARE:YOU:?"

for

char string [] = "HI:HOW:ARE:YOU:?"

With char string [] you have an array, and char * you have a pointer. When you declare an array, it will request space to allocate the size of your string. The char * string creates a pointer that points to a literal string.

The problem with char *string it is that the point should not be changed because string literals are typically stored in read-only memory, thus causing undefined behavior 33

( for more detail read this https://www.securecoding.cert.org/confluence/display/seccode/STR30-C.+Do+not+attempt+to+modify+string+literals )

Therefore, since with strtok the contents of the string is modified and broken into smaller strings (tokens) you got problems.

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