将天数添加到特定日期 [英] Adding days to specific day
问题描述
许多示例都是关于将天数添加到今天.但是如果我有不同的起始日怎么办?
Many examples are about adding days to this day. But how to do it, if I have different starding day?
例如(不起作用):
$day='2010-01-23';
// add 7 days to the date above
$NewDate= Date('$day', strtotime("+7 days"));
echo $NewDate;
上面的例子不起作用.我应该如何通过在日期位置放置其他内容来更改起始日期?
Example above does not work. How should I change the starding day by putting something else in the place of Date?
推荐答案
对于基于您的代码的非常基本的修复:
For a very basic fix based on your code:
$day='2010-01-23';
// add 7 days to the date above
$NewDate = date('Y-m-d', strtotime($day . " +7 days"));
echo $NewDate;
如果您使用的是 PHP 5.3+，则可以使用非常方便的新 DateTime 库:
If you are using PHP 5.3+, you can use the new DateTime libs which are very handy:
$day = '2010-01-23';
// add 7 days to the date above
$NewDate = new DateTime($day);
$NewDate->add(new DateInterval('P7D');
echo $NewDate->format('Y-m-d');
我现在完全改用DateTime，因为它非常强大.您还可以在实例化时轻松指定时区，即 new DateTime($time, new DateTimeZone('UTC')).您可以使用方法 add() 和 sub() 来更改 DateInterval 对象的日期.这是文档:
I've fully switched to using DateTime myself now as it's very powerful. You can also specify the timezone easily when instantiating, i.e. new DateTime($time, new DateTimeZone('UTC')). You can use the methods add() and sub() for changing the date with DateInterval objects. Here's documentation:
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