PHP:strtotime 返回“无"；“布尔"类型的 [英] PHP: strtotime returns "nothing" of type "boolean"

问题描述

我有变量 $EDate，我使用 strtotime 函数和这个变量不同的值，结果如下:

I have the variable $EDate, I used strtotime function with this variable with different values and the result was as following:

$EDate = 10-21-2013;    echo "strtotime($EDate)";   the result = nothing    and the type is boolean
$EDate = 09-02-2013;    echo "strtotime($EDate)";   the result = 1360386000 and the type is integer
$EDate = 09-30-2013;    echo "strtotime($EDate)";   the result = nothing    and the type is boolean
$EDate = 09-30-2013;    echo "strtotime($EDate)";   the result = nothing    and the type is boolean
$EDate = 07-02-2014;    echo "strtotime($EDate)";   the result = 1391749200 and the type is integer
$EDate = 10-12-2014;    echo "strtotime($EDate)";   the result = 1418187600 and the type is integer

谁能解释一下这个以及如何避免布尔结果?

Can anybody explain this and how to avoid the boolean result?

推荐答案

来自文档:

m/d/y 或 d-m-y 格式的日期通过查看各个组件之间的分隔符来消除歧义:如果分隔符是斜杠 (/)，则假定为美国 m/d/y；而如果分隔符是破折号 (-) 或点 (.)，则假定为欧洲 d-m-y 格式.

Dates in the m/d/y or d-m-y formats are disambiguated by looking at the separator between the various components: if the separator is a slash (/), then the American m/d/y is assumed; whereas if the separator is a dash (-) or a dot (.), then the European d-m-y format is assumed.

您的代码假定日期为 d-m-y 格式，并且会返回 FALSE，因为月份值不正确:

Your code assumes that the date is in d-m-y format, and will return FALSE since the month values are incorrect:

var_dump(strtotime('10-21-2013')); // no month 21
var_dump(strtotime('09-30-2013'));
var_dump(strtotime('09-30-2013'));

如果您希望能够使用自定义格式，请使用 DateTime::createFromFormat() 代替:

If you want to be able to use custom formats, use DateTime::createFromFormat() instead:

$date = DateTime::createFromFormat('m-d-Y', '10-21-2013');
echo $date->format('U');

演示！

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