如何对嵌套在结构数组中的结构数组进行排序 C [英] How to sort an array of structs nested in a array of structs C
问题描述
我知道有与此类似的帖子,但我无法理解它们,所以我也在制作一个,所以请不要将其标记为重复:)
I know there are similiar posts to this one but I can't get my head around them so I'm making one too so please don't mark this as a duplicate :)
我有 2 个嵌套的结构数组,其中外部结构是比赛,内部结构是来自这些比赛的船只数量.我想对内部结构进行排序,以便船按 time_to_complete_race
的升序排列,一旦完成此操作,我将分配数组中的第一条船 points = 4
,第二个points = 2
和第三个points = 1
.不过我还没有实现积分分配,所以请忽略这部分.
I've got 2 nested arrays of structs where the outer structs are races and the inner structs are the number of boats from those races. I want to sort the inner struct so that the boats are in ascending order of time_to_complete_race
and once I've done this I then assign the first boat in the array points = 4
, the second points = 2
and the thirdpoints = 1
. I haven't however implemented the points assinging yet so please ignore this part.
struct boat_data {
int ID;
int time_to_complete_race;
int points;
} boat_node;
typedef struct race_result {
char race_date[80];
int start_time;
int num_boats_competing;
struct boat_data boat_data[MAX_BOAT_NUMBER];
} race_node;
这是我用来对内部结构进行排序的代码:
Here is the code that I am using to sort the inner stucts:
void print_races(int races, race_ptr results[], member_node_ptr member) {
for(int race = 0; race < races; race++) {
printf("Race Date: %s\n", results[race].race_date);
printf("Race Start Time: %d\n", results[race].start_time);
printf("Number of Skippers: %d\n", results[race].num_boats_competing);
for(int boats = 0; boats < results[race].num_boats_competing; boats++) {
find_node_by_id(member, results[race].boat_data[boats].ID);
printf("\tTime to Complete Race in Seconds: %d\n",
results[race].boat_data[boats].time_to_complete_race);
}
printf("\n");
}
}
void print_sorted_races(int races, race_ptr results[], member_node_ptr member) {
race_ptr sorted_results[races];
struct boat_data temp;
int race, swap, boat;
for (race = 0; race < races; race++) {
sorted_results[race] = results[race];
}
for (race = 0; race < races; race++) {
for (boat = 0; boat< (sorted_results[race].num_boats_competing -1); boat++) {
for (swap = race + 1; swap < sorted_results[race].num_boats_competing; swap++) {
if (sorted_results[race].boat_data[swap].time_to_complete_race >
sorted_results[race].boat_data[boat].time_to_complete_race) {
temp = sorted_results[race].boat_data[boat];
sorted_results[race].boat_data[boat] = sorted_results[race].boat_data[swap];
sorted_results[race].boat_data[swap] = temp;
}
}
}
}
print_races(races, results, member);
}
推荐答案
通过尝试滚动你自己的排序例程而不是使用 qsort
由 C 库提供.使用 qsort
,您只需编写一个 compare 函数来比较 race_node的
boat_data[]
数组成员的元素代码>.比较函数原型为:
You are making things much harder and much more error prone by trying to roll-your-own sort routine rather than using qsort
provided by the C library. With qsort
all you need to do is write a compare function that compares elements of the boat_data[]
array member of race_node
. The compare function prototype is:
int compare (const void *a, const void *b)
所有a
和b
所在的位置,都是指向数组boat_data[]
元素的指针.因此,在 compare
中,您只需将 a
和 b
转换为正确的类型(例如 structboat_node const *pa = a, *pb = b;
或者如果您在第一个结构体上完成了 typedef
,只需 boat_node const *pa = a, *pb = b;
).
Where all a
and b
are, are pointers to elements of the array boat_data[]
. So within compare
you simply need to cast a
and b
to the correct type (e.g. struct boat_node const *pa = a, *pb = b;
or if you complete your typedef
on your first struct, simply boat_node const *pa = a, *pb = b;
).
然后比较 pa->time_to_complete_race
和 pb->time_to_complete_race
返回 -1
如果 pa->time_to_complete_race
排序 before pb->time_to_complete_race
或 1
如果 pb->time_to_complete_race
排序 之前 pa->time_to_complete_race
,或者 0
如果它们相等(注意:完全一样 strcmp()
确实)
Then compare pa->time_to_complete_race
and pb->time_to_complete_race
returning -1
if pa->time_to_complete_race
sorts before pb->time_to_complete_race
or 1
if pb->time_to_complete_race
sorts before pa->time_to_complete_race
, or 0
if they are equal (note: exactly the way strcmp()
does)
你的 compare
函数是:
int compare (const void *a, const void *b)
{
boat_node const *pa = a, *pb = b;
return (pa->time_to_complete_race > pb->time_to_complete_race) -
(pa->time_to_complete_race < pb->time_to_complete_race);
}
注意:在完成typedef
后,例如
typedef struct boat_data {
int ID;
int time_to_complete_race;
int points;
} boat_node;
然后对作为 race_node Race
成员的 boat_data[]
数组进行排序,您只需调用:
Then to sort your boat_data[]
array which is a member of race_node race
, all you do is call:
qsort (race.boat_data, race.num_boats_competing,
sizeof *race.boat_data, compare);
(完成!)
新的 C 程序员常常对使用 qsort
犹豫不决,因为他们不知道如何编写 compare 函数.在您了解 a
和 b
只是指向 元素的任何要排序的元素这一事实之后,您可以轻松地提供一个强制转换正确的类型,然后进行比较,告诉 qsort
您希望它如何排序.
New C programmers are often hesitant to use qsort
because they don't know how to write the compare function. After you make friends with the fact that a
and b
are just pointers to elements of whatever you are sorting, you can easily provide a cast to the proper type and then a comparison that tells qsort
how you want it sorted.
在这种情况下,您只需要按 time_to_complete_race
排序的 boat_data[]
数组.return (a > b) - (a < b)
形式只是一种避免潜在溢出的简便方法,如果您想 return a - b;
其中,例如,a
是一个大的负整数,b
是一个大的正整数.
In this case you simply want the array of boat_data[]
sorted by time_to_complete_race
. The return (a > b) - (a < b)
form is simply a convenient way to avoid potential overflow were you tempted to return a - b;
where, e.g., a
is a large negative integer and b
a large positive integer.
完整示例
#include <stdio.h>
#include <stdlib.h>
#define MAX_BOAT_NUMBER 10
typedef struct boat_data {
int ID;
int time_to_complete_race;
int points;
} boat_node;
typedef struct race_result {
char race_date[80];
int start_time;
int num_boats_competing;
boat_node boat_data[MAX_BOAT_NUMBER];
} race_node;
int compare (const void *a, const void *b)
{
boat_node const *pa = a, *pb = b;
return (pa->time_to_complete_race > pb->time_to_complete_race) -
(pa->time_to_complete_race < pb->time_to_complete_race);
}
int main (void) {
race_node race = { .race_date = "11/26/19",
.start_time = 1400,
.num_boats_competing = 3,
.boat_data = {{ 1, 23, 0 },
{ 2, 21, 0 },
{ 3, 22, 0 }} };
qsort (race.boat_data, race.num_boats_competing,
sizeof *race.boat_data, compare);
for (int i = 0; i < race.num_boats_competing; i++)
printf ("%2d %4d %d\n", race.boat_data[i].ID,
race.boat_data[i].time_to_complete_race,
race.boat_data[i].points);
}
示例使用/输出
points
成员都剩下0
:
$ ./bin/boat_race
2 21 0
3 22 0
1 23 0
比尝试编写自己的排序要容易得多.仔细检查一下,如果您还有其他问题,请告诉我.
Much easier than trying to write your own sort. Look things over and let me know if you have further questions.
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