“路径 login.page 不以“/"开头字符"更改java版本后的消息异常 [英] "Path login.page does not start with a "/" character" message exception after changing java version

问题描述

我有一个 Web 应用程序，它使用以下内容:雄猫5.0支柱 1.0Java 1.5

I have a web application which worked with the following: Tomcat 5.0 Struts 1.0 Java 1.5

我必须切换到 Java 1.6.当我尝试这样做时，我收到了以下堆栈我的浏览器中的异常:

I have to switch to Java 1.6.When I tried to do that, i received the following stack of exception in my browser:

javax.servlet.ServletException: Path login.page does not start with a "/" character
    org.apache.struts.chain.ComposableRequestProcessor.process(ComposableRequestProcessor.java:286)
    org.apache.struts.action.ActionServlet.process(ActionServlet.java:1913)
    org.apache.struts.action.ActionServlet.doGet(ActionServlet.java:449)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:743)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
    org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:72)
    org.apache.jasper.runtime.PageContextImpl.doForward(PageContextImpl.java:712)
    org.apache.jasper.runtime.PageContextImpl.forward(PageContextImpl.java:682)
    org.apache.jsp.index_jsp._jspService(index_jsp.java:45)
    org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:133)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
    org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:311)
    org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:301)
    org.apache.jasper.servlet.JspServlet.service(JspServlet.java:248)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
    org.springframework.web.filter.CharacterEncodingFilter.doFilterInternal(CharacterEncodingFilter.java:78)
    org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:77)

根本原因

java.lang.IllegalArgumentException: Path login.page does not start with a "/" character
    org.apache.struts.chain.commands.servlet.PerformForward.handleAsForward(PerformForward.java:107)
    org.apache.struts.chain.commands.servlet.PerformForward.perform(PerformForward.java:96)
    org.apache.struts.chain.commands.AbstractPerformForward.execute(AbstractPerformForward.java:54)
    org.apache.struts.chain.commands.ActionCommandBase.execute(ActionCommandBase.java:51)
    org.apache.commons.chain.impl.ChainBase.execute(ChainBase.java:190)
    org.apache.commons.chain.generic.LookupCommand.execute(LookupCommand.java:304)
    org.apache.commons.chain.impl.ChainBase.execute(ChainBase.java:190)
    org.apache.struts.chain.ComposableRequestProcessor.process(ComposableRequestProcessor.java:283)
    org.apache.struts.action.ActionServlet.process(ActionServlet.java:1913)
    org.apache.struts.action.ActionServlet.doGet(ActionServlet.java:449)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:743)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
    org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:72)
    org.apache.jasper.runtime.PageContextImpl.doForward(PageContextImpl.java:712)
    org.apache.jasper.runtime.PageContextImpl.forward(PageContextImpl.java:682)
    org.apache.jsp.index_jsp._jspService(index_jsp.java:45)
    org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:133)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
    org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:311)
    org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:301)
    org.apache.jasper.servlet.JspServlet.service(JspServlet.java:248)
    javax.servlet.http.HttpServlet.service(HttpServlet.java:856)
    org.springframework.web.filter.CharacterEncodingFilter.doFilterInternal(CharacterEncodingFilter.java:78)
    org.springframework.web.filter.OncePerRequestFilter.doFilter(OncePerRequestFilter.java:77)

推荐答案

看起来像是对 "login.page" 发出的请求，正如异常所指示的那样，它不是以 <开头的代码>"/".尝试改为请求 "/login.page".

It looks like a request is made to "login.page", which as the exception indicates, does not start with a "/". Try requesting for "/login.page" instead.

大多数 servlet 库要求路径名以 "/" 开头.例如:javax.servlet.ServletContext#getRequestDispatcher:

Most servlet libraries require that pathnames begins with a "/". For example: javax.servlet.ServletContext#getRequestDispatcher:

路径名必须以 "/" 开头，并被解释为相对于当前上下文根.使用 getContext 为外部上下文中的资源获取 RequestDispatcher.

The pathname must begin with a "/" and is interpreted as relative to the current context root. Use getContext to obtain a RequestDispatcher for resources in foreign contexts.

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