通过红宝石哈希数组迭代 [英] iterate through array of hashes in ruby

问题描述

所以，如果我有像这样的哈希值的数组：（红宝石初学者）

so if I have an array of hashes like so: (ruby beginner)

input =  [

{"last_name"=>"Gay", "first_name"=>"Rudy", "display_name"=>"Rudy Gay", "position"=>"SF", "minutes"=>39, "points"=>25, "assists"=>6}, 
{"last_name"=>"Collison", "first_name"=>"Darren", "display_name"=>"Darren Collison", "position"=>"PG", "minutes"=>39, "points"=>14, "assists"=>4}

]

如何将我通过遍历数组以及通过散列每个迭代有这样的事情：

how would i iterate through the array as well as to iterate through each hash to have something like this:

PLAYER1 = {DISPLAY_NAME =>盖伊，位置=>SF}

player1 = {display_name=>"rudy gay", "position"=>"SF"}

player2 = {DISPLAY_NAME =>达伦 - 科里森，位置=>PG}

player2 = {display_name=>"darren collison", "position"=>"PG"}

它会是这样的。

input.each do  |x|
Player.create(name: x['display_name'], position: x['position']
end

（假设我有一个球员模型）

(assuming I have a player model)

有没有更好的方式来实现这一目标？

Is there a better way to achieve this?

谢谢！

推荐答案

鉴于你输入：

input =  [
  { "last_name"=>"Gay", ... }, 
  { "last_name"=>"Collison", ...}
]

如果所有这些钥匙（姓氏，FIRST_NAME，DISPLAY_NAME）都在播放器模型$ P ​​$ psent，你可以：

If all of those keys (last_name, first_name, display_name) are present in the Player model, you can just:

input.each do |x|
  Player.create(x)
end

由于创建将属性分配的哈希值。但是，甚至更好，你甚至都不需要遍历：

Since create will take a hash of attributes to assign. But, even better, you don't even need to iterate:

Player.create(input)

ActiveRecord的将通过所有这些，如果你给它哈希值的数组。

ActiveRecord will go through them all if you give it an array of hashes.

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