自动包装自定义 XML 标签并对其进行编号 [英] Automatically wrap custom XML tags and numbering them

问题描述

我有一个需要格式化为 XML 的游戏的对话脚本，格式如下...

I have a dialogue script for a game that needs to be formatted in XML, with following format...

<line id='1'> .............. </line>
<line id='2'> .............. </line>
<line id='3'> .............. </line>
....
<line id='n'> .............. </line>

我现在给出的对话脚本是用普通格式编写的，我只需要用上面的 XML 标签包装每一行.

Dialogue script I've given right now is written in plain format, I only need to wrap each lines in XML tags above.

有没有办法让流程自动化?

Is there a way to automate the process?

推荐答案

您可以通过两个步骤来实现.首先，在文本文件的每一行的开头添加一个行号.然后，将每一行包装在您需要的 XML 标记中.

You can achieve this in two steps. First, add a line number to the start of each line of your text file. Then, wrap each line in the <line> XML tags which you need.

要生成行号，您可以使用列编辑器模式.首先，通过此查找和替换在每行的开头插入一个空格:

To generate line numbers, you can use column editor mode. First, insert a space the start of each line via this find and replacement:

查找:

(.*)

替换:

 $1 (single space followed by $1)

然后使用列编辑器模式在每一行的开头插入一个生成的行号.有关如何执行此操作的详细信息，请参阅此处.此时，您的数据应如下所示:

Then use column editor mode to insert a generated line number at the start of each line. See here for more information on how to do this. At this point, your data should look something like this:

1 Here is line one.
2 Here is line two.
3 Here is line three.
...
111 Here is line one hundred eleven.

现在您可以进行第二次查找和替换以将每一行包裹在 标记中:

Now you can do a second find and replacement to wrap each line in the <line> tag:

查找:

([0-9]+)\s+(.*)

替换:

<line id='$1'>$2</line>

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