在 Sublime 3 中构建 Java [英] Java Build in Sublime 3

问题描述

我正在尝试建立一个构建，以便我可以在 sublime 3 中编译和运行 Java.我的构建系统不工作.

I'm trying to set up a build so that I can compile and run Java in sublime 3. My build system isn't working.

"cmd": "java ${file_name} && java ${file_base_name}",
"file_regex": "^[ ]file \"(...?)\", line ([0-9]*)",
"path":"C:\\ProgramData\\Oracle\\Java\\javapath\\java.exe",
"selector": "source.java",
"shell":true

我将此构建保存到我的包中，它出现在构建菜单中，但是当我尝试运行它时，它说没有构建工作.

I have this build saved to my packages and it appears in the build menu, but when I try and run it, it says that there is no build working.

推荐答案

请阅读 构建系统文档，了解有关如何构建 .sublime-build 文件的信息."cmd" 和 "path" 是列表，而不是字符串，因此这可能是您收到错误的原因之一.正如我在评论中提到的，另一个原因是您正在尝试使用 java 而不是 javac 编译您的 .java 文件.最后，您的 "path" 不正确 —它应该指向目录列表，而不是文件.这可能更适合您:

Please read the build system documentation for information on how to structure .sublime-build files. "cmd" and "path" are lists, not strings, so that's one reason you may be getting an error. Another reason, as I mentioned in the comments, is that you are trying to compile your .java file with java instead of javac. Finally, your "path" is incorrect — it should point to a list of directories, not files. This may work better for you:

{
    "cmd": ["javac", "${file_name}", "&&", "java", "${file_base_name}"],
    "file_regex": "^[ ]file \"(...?)\", line ([0-9]*)",
    "path": ["C:\\ProgramData\\Oracle\\Java\\javapath"],
    "selector": "source.java",
    "shell": true
}

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