Python 子进程:打开的文件太多 [英] Python Subprocess: Too Many Open Files

问题描述

我正在使用子进程调用另一个程序并将其返回值保存到一个变量中.这个过程在一个循环中重复，在几千次之后程序崩溃并出现以下错误:

I am using subprocess to call another program and save its return values to a variable. This process is repeated in a loop, and after a few thousands times the program crashed with the following error:

Traceback (most recent call last):
  File "./extract_pcgls.py", line 96, in <module>
    SelfE.append( CalSelfEnergy(i) )
  File "./extract_pcgls.py", line 59, in CalSelfEnergy
    p = subprocess.Popen(cmd, stdout=subprocess.PIPE, shell=True)
  File "/usr/lib/python3.2/subprocess.py", line 745, in __init__
    restore_signals, start_new_session)
  File "/usr/lib/python3.2/subprocess.py", line 1166, in _execute_child
    errpipe_read, errpipe_write = _create_pipe()
OSError: [Errno 24] Too many open files

非常感谢您对如何解决此问题的任何想法！

Any idea how to solve this issue is much appreciated!

从评论提供的代码:

cmd = "enerCHARMM.pl -parram=x,xtop=topology_modified.rtf,xpar=lipid27_modified.par,nobuildall -out vdwaals {0}".format(cmtup[1])
p = subprocess.Popen(cmd, stdout=subprocess.PIPE, shell=True)
out, err = p.communicate()

推荐答案

我想问题是由于我正在使用子进程处理打开的文件:

I guess the problem was due to the fact that I was processing an open file with subprocess:

cmd = "enerCHARMM.pl -par param=x,xtop=topology_modified.rtf,xpar=lipid27_modified.par,nobuildall -out vdwaals {0}".format(cmtup[1])
p = subprocess.Popen(cmd, stdout=subprocess.PIPE, shell=True)

这里的 cmd 变量包含刚刚创建但尚未关闭的文件的名称.然后 subprocess.Popen 对该文件调用系统命令.多次执行此操作后，程序崩溃并显示该错误消息.

Here the cmd variable contain the name of a file that has just been created but not closed. Then the subprocess.Popen calls a system command on that file. After doing this for many times, the program crashed with that error message.

所以我从中学到的信息是

So the message I learned from this is

关闭您创建的文件，然后对其进行处理

Close the file you have created, then process it

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