忽略 CalledProcessError [英] Ignoring CalledProcessError

问题描述

我正在使用 subprocess 模块和 check_output() 在我的 Python 脚本中创建一个虚拟 shell，它适用于返回零退出状态的命令，然而，对于那些不返回异常的人，它不会打印在普通 shell 的输出中显示的错误.

例如，我希望有这样的工作:

<预><代码>>>>shell('cat 不存在的文件')cat: non-existing-file: 没有那个文件或目录

但是，这种情况发生了:

<预><代码>>>>shell('cat 不存在的文件')CalledProcessError:命令cat non-existing-file"返回非零退出状态 1(文件/usr/lib/python2.7/subprocess.py"，第 544 行，在 check_output 中)

即使我可以使用 try 和 except 删除 Python 异常消息，我仍然想要 cat: non-existing-file: No such file 或目录显示给用户.

我该怎么做?

shell():

def shell(命令):输出 = subprocess.check_output(命令，shell=True)完成 = output.split('\n')对于线完成:印刷线返回

解决方案

可能是这样的?

def shell(命令):尝试:输出 = subprocess.check_output(命令，shell=True，stderr=subprocess.STDOUT)除了例外，e:输出 = str(e.output)完成 = output.split('\n')对于完成的行:印刷线返回

I am using the subprocess module and check_output() to create a virtual shell in my Python script, and it works fine for commands that return a zero exit status, however for ones that don't it returns an exception without printing the error that would have been displayed in the output on a normal shell.

For instance, I would expect something to work like this:

>>> shell('cat non-existing-file')
cat: non-existing-file: No such file or directory

But instead, this happens:

>>> shell('cat non-existing-file')
CalledProcessError: Command 'cat non-existing-file' returned non-zero exit status 1 (file "/usr/lib/python2.7/subprocess.py", line 544, in check_output)

Even though I could remove the Python exception message using try and except, I still want the cat: non-existing-file: No such file or directory to display to the user.

How would I go about doing this?

shell():

def shell(command):
    output   = subprocess.check_output(command, shell=True)
    finished = output.split('\n')

    for line in finished:
      print line
    return

解决方案

Something like this perhaps?

def shell(command):
    try:
        output = subprocess.check_output(command, shell=True, stderr=subprocess.STDOUT)
    except Exception, e:
        output = str(e.output)
    finished = output.split('\n')
    for line in finished:
        print line
    return

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