如何使用python终止外部程序或窗口 [英] How to terminate external program or window using python
问题描述
我正在尝试关闭程序,在这种情况下是 Spotify,但我不断收到语义错误.这是我的代码:
I am trying to close the program, in this case spotify, but I am keep getting semantic mistake. Here is my code:
sup_programs.txt
sup_programs.txt
{
'spotify': ['C:/Users/Daniiar/AppData/Roaming/Spotify/Spotify.exe']
}
脚本:
class Path(object):
import ast
sup_programs_txt = open('sup_programs.txt', 'r')
s_p = sup_programs_txt.read()
paths = ast.literal_eval(s_p)
sup_programs_txt.close()
paths = Path().paths
program_name = 'spotify'
def open_program(path_name):
import subprocess
subprocess.Popen(path_name)
open_program(paths[program_name])
def close_program(path_name):
import subprocess
p = subprocess.Popen(path_name)
p.terminate()
yes = input(" ... ")
if 'close' in yes or 'yes' in yes:
close_program(paths[program_name])
else:
print('too bad')
我使用了 kill() 和 terminate() 他们都没有工作和 os.system('TASKKILL ')是否有其他方法或错误使用现有方法?
I used kill() and terminate() neither of them have worked and os.system('TASKKILL ') Is there any other methods or am using existing ones incorrectly?
顺便说一句,我使用的是 windows 10 和 python 3.5 .感谢您的帮助
BTW, I am using windows 10 and python 3.5 . Thank you for your help
推荐答案
你的 open_program
函数是递归的???
your open_program
function is recursive ???
无论如何,要打开您的程序,您可以通过路径名来完成.然后它返回一个子进程的句柄.要关闭它,只需调用该句柄上的终止方法
Anyway, to open your program, you can do it by the path name. It then returns a handle on a subprocess. To close it, just call the terminate method on that handle
下面的例子打开记事本,等待 3 秒,然后关闭它.
example below opens notepad, waits 3 seconds, then closes it.
import time
import subprocess
def open_program(path_name):
return subprocess.Popen(path_name)
def close_program(p):
p.terminate()
p=open_program("notepad")
time.sleep(3)
close_program(p)
这篇关于如何使用python终止外部程序或窗口的文章就介绍到这了,希望我们推荐的答案对大家有所帮助,也希望大家多多支持IT屋!