删除零然后垂直塌矩阵 [英] Removing zeros and then vertically collapse the matrix

问题描述

在MATLAB，说我有一组方阵，比如说A，用跟踪（A）= 0如下：

In MATLAB, say I have a set of square matrices, say A, with trace(A)=0 as follows:

例如，

A = [0 1 2; 3 0 4; 5 6 0] 

我怎样才能去除零然后垂直塌矩阵成为如下：

How can I remove the zeros and then vertically collapse the matrix to become as follow:

A_reduced = [1 2; 3 4; 5 6]

更一般地，如果零所用的柱的任何地方出现什么（即，不一定在长对角线）？假设，当然，该零点的所有列的总数是相同的。

More generally, what if the zeroes can appear anywhere in the column (i.e., not necessarily at the long diagonal)? Assuming, of course, that the total number of zeros for all columns are the same.

该矩阵可以说是相当大的（数百点¯x数百尺寸）。因此，一个有效的方法将是AP preciated。

The matrix can be quite big (hundreds x hundreds in dimension). So, an efficient way will be appreciated.

推荐答案

• 要融为一体preSS矩阵垂直（假设每列具有相同数量的零）：

• To compress the matrix vertically (assuming every column has the same number of zeros):

  A_reduced_v = reshape(nonzeros(A), nnz(A(:,1)), []);
  




• 要融为一体preSS矩阵水平（假设每一行有相同数量的零）：

• To compress the matrix horizontally (assuming every row has the same number of zeros):

  A_reduced_h = reshape(nonzeros(A.'), nnz(A(1,:)), []).';
  




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