仅显示文本文件中的前五行 [英] Show only five first lines from text file

问题描述

我有这个代码(来自 SteAp):

I have this code (from SteAp):

<?php    
$file = fopen("news/news_2013.txt", "r");

$i = 0;
while (!feof($file)) {
    $posts[] = fgets($file);
}
fclose($file);

foreach ($posts as $rawPost ){

    $datePart = substr( $rawPost, 0, 19 );
    $newsPart = substr( $rawPost, 20, 10000 );

    echo $datePart . ': ' . $newsPart . '<br />';
}
?>

我在这里使用它:http://flamencopeko.net/news.工作完美.

I use it here: http://flamencopeko.net/news. Works perfect.

我正在尝试为主页制作一个仅显示五个最新行的版本.像这样:http://flamencopeko.net/index2.php 但仅限前五名.所以 while (!feof($file)) 不适用于此目的.

I'm trying to make a version for the main page that shows only the five newst lines. Like this: http://flamencopeko.net/index2.php But only with the top five posts. So while (!feof($file)) will not work for this purpose.

建议?

推荐答案

只需使用计数器即可跳出循环

Just use a counter and break out of the loop

$i = 0;
while (!feof($file)) {
    $posts[] = fgets($file);
    $i++;
    if ($i >= 5) break;
}

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