如何在 Swift 中使用 substringToIndex? [英] How to use substringToIndex in Swift?
问题描述
我在这一行遇到编译器错误:
I get compiler error at this line:
UIDevice.currentDevice().identifierForVendor.UUIDString.substringToIndex(8)
类型String.Index"不符合协议IntegerLiteralConvertible"
我的目的是获取子字符串,但如何获取?
My intention is to get the substring, but how?
推荐答案
在 Swift 中,String
索引遵循字素簇,并且 IndexType
不是 Int代码>.您有两种选择 - 将字符串(您的 UUID)转换为 NSString,并将其用作before",或者创建第 n 个字符的索引.
In Swift, String
indexing respects grapheme clusters, and an IndexType
is not an Int
. You have two choices - cast the string (your UUID) to an NSString, and use it as "before", or create an index to the nth character.
两者都如下图所示:
然而,该方法在 Swift 版本之间发生了根本性的变化.向下阅读以获取更高版本...
However, the method has changed radically between versions of Swift. Read down for later versions...
Swift 1
let s: String = "Stack Overflow"
let ss1: String = (s as NSString).substringToIndex(5) // "Stack"
//let ss2: String = s.substringToIndex(5)// 5 is not a String.Index
let index: String.Index = advance(s.startIndex, 5)
let ss2:String = s.substringToIndex(index) // "Stack"
CMD-单击 substringToIndex
会令人困惑地将您带到 NSString
定义,但是 CMD-单击 String
会发现以下内容:
CMD-Click on substringToIndex
confusingly takes you to the NSString
definition, however CMD-Click on String
and you will find the following:
extension String : Collection {
struct Index : BidirectionalIndex, Reflectable {
func successor() -> String.Index
func predecessor() -> String.Index
func getMirror() -> Mirror
}
var startIndex: String.Index { get }
var endIndex: String.Index { get }
subscript (i: String.Index) -> Character { get }
func generate() -> IndexingGenerator<String>
}
斯威夫特 2
正如评论员@DanielGalasko 指出的 advance
现在已经改变了......
Swift 2
As commentator @DanielGalasko points out advance
has now changed...
let s: String = "Stack Overflow"
let ss1: String = (s as NSString).substringToIndex(5) // "Stack"
//let ss2: String = s.substringToIndex(5)// 5 is not a String.Index
let index: String.Index = s.startIndex.advancedBy(5) // Swift 2
let ss2:String = s.substringToIndex(index) // "Stack"
斯威夫特 3
在 Swift 3 中,它又发生了变化:
Swift 3
In Swift 3, it's changed again:
let s: String = "Stack Overflow"
let ss1: String = (s as NSString).substring(to: 5) // "Stack"
let index: String.Index = s.index(s.startIndex, offsetBy: 5)
var ss2: String = s.substring(to: index) // "Stack"
斯威夫特 4
在 Swift 4 中,还有另一个变化:
Swift 4
In Swift 4, yet another change:
let s: String = "Stack Overflow"
let ss1: String = (s as NSString).substring(to: 5) // "Stack"
let index: String.Index = s.index(s.startIndex, offsetBy: 5)
var ss3: Substring = s[..<index] // "Stack"
var ss4: String = String(s[..<index]) // "Stack"
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