正则表达式:对 url 字符串的两个斜杠之间的倒数第二个值进行子串 [英] Regex: Substring the second last value between two slashes of a url string

问题描述

我有一个这样的字符串:

I have a string like this:

http://www.example.com/value/1234/different-value

如何提取1234?

注意:末尾可能有斜线:

Note: There may be a slash at the end:

http://www.example.com/value/1234/different-value
http://www.example.com/value/1234/different-value/

推荐答案

/([^/]+)(?=/[^/]+/?$)

应该可以.您可能需要根据您使用的语言对其进行不同的格式化.例如，在 Ruby 中，它是

should work. You might need to format it differently according to the language you're using. For example, in Ruby, it's

if subject =~ /\/([^\/]+)(?=\/[^\/]+\/?\Z)/
    match = $~[1]
else
    match = ""
end

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