如何获取整个单词使用子字符串? [英] how to get the whole words use substring?

问题描述

我有字符串 String fulltext = "我想创建一些文本，但我不知道 creater34r3 是什么，";

我有子字符串 String subtext = "create s"; 或 "create som" 或 "create so"..

如何获取subtext 的完整单词?(在本例中为create some"或create")

Pattern.compile("\\b(" + subtext + "\\p{Alnum}+)"); - 不工作 =(

解决方案

它可以工作，但是您应该使用 Matcher.find()(它会找到第一次出现的正则表达式)而不是 Matcher.matches()(针对整个字符串测试正则表达式).

Matcher m = Pattern.compile("\\b(" + subtext + "\\p{Alnum}*)").matcher(fulltext);System.out.println(m.find());System.out.println(m.group(1));

印刷品

真创造一些

正如 Sean Landsman 所指出的，它应该是 \\p{Alnum}*(因为潜台词可能出现在字符串的末尾，如果 + 使用了量词).

I have string String fulltext = "I would like to create some text and i dont know what creater34r3, ";

and i have substring String subtext = "create s"; or "create som" or "create so"..

how to get the whole words for subtext ? (in this case "create some" or "create")

Pattern.compile("\\b(" + subtext + "\\p{Alnum}+)"); - not work =(

解决方案

It works, but you should use Matcher.find() (which finds the first occurrence of the regex) instead of Matcher.matches() (which tests the regexp against the whole string).

Matcher m = Pattern.compile("\\b(" + subtext + "\\p{Alnum}*)").matcher(fulltext);
System.out.println(m.find());
System.out.println(m.group(1));

Prints

true
create some

Edit: as Sean Landsman pointed, it should be \\p{Alnum}* (because subtext may occur at the end of the string, and would not be matched if a + quantifier were used).

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