删除R中字符串的中间部分 [英] Remove middle part of string in R

问题描述

如何去除刺的中间部分?例如，取字符串 - '2018_002.Feb'.对于此示例，我想删除002."，以便获得2018_Feb"

How do I remove the middle part of a sting? For example, take the string - '2018_002.Feb'. For this example, I want to remove '002.', so that I get '2018_Feb'

谁能帮帮我?谢谢！

推荐答案

我喜欢使用 stringr 包而不是基本的 r 包来处理字符串，因为我发现函数的语法更多持续的.

I like to use the stringr package as opposed to the base r packages for string manipulations because I find the syntax for the functions more consistent.

library(stringr)

var = "2018_002.Feb"

str_replace(var, pattern = "_\\d+\\.", replacement = "_")

# [1] "2018_Feb"

使用str_replace()，您基本上是在字符串中搜索模式并将其替换为其他内容.通常替换将只是一个空的 ""，但在这种情况下，在函数找到 _ 字符的地方开始搜索更容易，因为它相当独特.从那里开始，您希望匹配该期间之后的所有数字.

With the str_replace() you are basically searching a pattern in the string an replacing it with something else. Often the replacement will just be an empty "", but in this case, it is easier to start the search where the function finds a _ character because it is rather unique. From there you want to match on all the numbers that come after up to the period.

我建议学习一些关于正则表达式的知识.R中的基本正则表达式备忘单是一个很好的资源.

I recommend learning a bit about regular expression. The Basic Regular Expressions in R Cheat Sheet is a good resource.

这个问题的正则表达式是这样的:

The regex for this problem reads something like this:

• 首先找到_后跟数字\\d的字符并保持匹配数字 + 直到您到达句点 \\.
• 找到匹配项_002."后，将其替换为_"

• first find _ character that is followed by a number \\d and keep matching numbers + until you reach a period \\.
• Once you find this match "_002.", replace it with "_"

希望这是可以理解的！

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