如何从一行中总结任意数量的用户输入数字 [英] How to sum any amount of user inputted numbers from a single line

问题描述

试图弄清楚如何从用户那里获取任意数量的输入数字并将它们加在一起

Trying to figure out how I would take any amount of inputted numbers from a user and add them together

示例用户输入:1 2 3 4总和 = 10

Example user input: 1 2 3 4 Sum = 10

用户可以输入任意数量的数字，而不是指定数量，所以如果他想添加 1 2 3 4 5 6 7 8 9 10 11 12 13，则将它们加起来为 91

The user can put any amount of numbers in not a specified amount so if he wanted to add 1 2 3 4 5 6 7 8 9 10 11 12 13, it would sum them all up to 91

提前感谢您的帮助.

import java.util.Scanner;

public class test
{
    public static final int SENTINEL = -1;
    public static void main(String[] args) {
        Scanner kb = new Scanner(System.in);
        int score = 0;
        int sum = 0;

        System.out.println("Enter numbers here");
        while (score >= 0) {
            if (score <= -1) {
            score = kb.nextInt();
            sum += score;
            score = 0;
        }
            System.out.println(sum);
    }
  }
}

<小时>

感谢 libik 的所有时间和帮助，这里是完成的代码.

---

Thanks to libik for all his time and help, here is the finished code.

import java.util.Scanner;

public class JavaApplication1156 {

    public static void main(String[] args) {
    System.out.println("Enter numbers here");
    int sum;
    do {
        Scanner kb = new Scanner(System.in);
        int score = 0;
        sum = 0;
        String line = kb.nextLine();
        kb = new Scanner(line); //has to do this to make the kb.hasNexInt() work.
        while (kb.hasNextInt()) {
            score = kb.nextInt();
            sum += score;
        }
        if (sum <= -1)
        System.out.println("Application ended");
        else if (sum >= 0)
        System.out.println("Sum = " + sum);

    } while (sum != -1);
  }

}

推荐答案

其实很容易

import java.util.Scanner;

public class JavaApplication115 {

    public static void main(String[] args) {
        System.out.println("write numbers, if you write zero, program ends");
        Scanner input = new Scanner(System.in); //just copy-and paste this line, you dont have to understand it yet.
        int number;
        int sum = 0;
        do {
            number = input.nextInt(); //this reads number from input and store its value in variable number
            sum+= number; //here you add number to the total sum
        } while(number != 0); //just repeat cycle as long as number is not zero

        System.out.println("Sum is : " + sum);
    }

}

<小时>

基于您的代码的工作代码:

---

Working code based on your code :

public static void main(String[] args) {
    Scanner kb = new Scanner(System.in);
    int score = 0;
    int sum = 0;

    System.out.println("Enter numbers here");
    String line = kb.nextLine();

    kb = new Scanner(line); //has to do this to make the kb.hasNexInt() work.
    while (kb.hasNextInt()) {
        score = kb.nextInt();
        sum += score;
    }
    System.out.println(sum);
}

<小时>

另外，如果您对最小"版本感兴趣，它与之前的版本相同，但使用尽可能少的代码，这里是:

---

Also if you are interested in "minimal" version, which is the same as the one before, but using as less code as possible, here it is :

public static void main(String[] args) {
    int sum = 0;
    System.out.println("Enter numbers here");
    Scanner kb = new Scanner((new Scanner(System.in)).nextLine()); //has to do this to make the kb.hasNexInt() work.
    while (kb.hasNextInt()) {
        sum += kb.nextInt();
    }
    System.out.println(sum);
}

<小时>

找到每行的总和，只要总和不为零(基于第二个代码块):

---

Find sum of each line as long as sum is not zero (based on second block of code) :

public static void main(String[] args) {
    System.out.println("Enter numbers here");
    int sum;
    do {
        Scanner kb = new Scanner(System.in);
        int score = 0;
        sum = 0;
        String line = kb.nextLine();
        kb = new Scanner(line); //has to do this to make the kb.hasNexInt() work.
        while (kb.hasNextInt()) {
            score = kb.nextInt();
            sum += score;
        }
        System.out.println("Sum = " + sum);
    } while (sum != 0);
}

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