是否有一个函数在C#中的字节数组做圆周bitshift? [英] Is there a function to do circular bitshift for a byte array in C#?
问题描述
我似乎无法找到,如果有一个内置的方式做一个字节数组的圆形bitshift,什么C的的 ROL和ROR 的使用单个字节办?
让我解释一下,说,我有一个数组(二进制):
[0] = 11001110
[1] = 01000100
[2] = 10100001
,然后如果我想要做的 ROL_Array(1位)
或移动比特1比特的左边,我会得到:
[0] = 10011100
[1] = 10001001
[2] = 01000011
或者,如果我想要做的 ROR_Array(2位)
或移动位2位的权利,我会得到:
[0] = 00110011
[1] = 01010001
[2] = 10101000
这并不像你想象的那么简单。这里有一个快速版本的线程被关闭前:
公共静态的byte [] ROL_ByteArray(字节[]编曲,诠释nShift)
{
//执行'改编'由'nShift位向左逐位循环移位
//返回:
// =结果
字节[] = resArr新的字节[arr.Length] 如果(arr.Length大于0)
{
INT nByteShift = nShift /(的sizeof(字节)* 8); // @ dasblinkenlight的修正后调整
INT nBitShift = nShift%(的sizeof(字节)* 8); 如果(nByteShift> = arr.Length)
nByteShift%= arr.Length; INT S = arr.Length - 1;
INT D =秒 - nByteShift; 对于(INT nCnt = 0; nCnt< arr.Length; nCnt ++,D--,S--)
{
而(D℃,)
D + = arr.Length;
而(S℃,)
S + = arr.Length; 字节字节= ARR [S]。 resArr [D]。| =(字节)(字节<< nBitShift);
resArr [D> 0? ð - 1:resArr.Length - 1] | =(字节)(字节>>(的sizeof(字节)* 8 - nBitShift));
}
} 返回resArr;
}
和这里的测试:
字节[] =改编新的字节[] {
Convert.ToByte(11001110,2),
Convert.ToByte(01000100,2),
Convert.ToByte(10100001,2),
};字节[] = ARR2 Auth.ROL_ByteArray(ARR,1);字符串SSS =;
的for(int i = 0; I< arr2.Length;我++)
SSS + = Convert.ToString(ARR2 [I],2)+,;的Debug.WriteLine(SSS);
I can't seem to find if there's a built-in way to do a circular bitshift of a byte array, what C's ROL and ROR used to do with a single byte?
Let me explain, say, I have an array (in binary):
[0] = 11001110
[1] = 01000100
[2] = 10100001
and then if I want to do ROL_Array(1 bit)
or move bits 1 bit to the left, I'd get:
[0] = 10011100
[1] = 10001001
[2] = 01000011
or, if I want to do ROR_Array(2 bits)
or move bits 2 bits to the right, I'd get:
[0] = 00110011
[1] = 01010001
[2] = 10101000
This is not as simple as you'd think. Here's a quick version before this thread gets closed:
public static byte[] ROL_ByteArray(byte[] arr, int nShift)
{
//Performs bitwise circular shift of 'arr' by 'nShift' bits to the left
//RETURN:
// = Result
byte[] resArr = new byte[arr.Length];
if(arr.Length > 0)
{
int nByteShift = nShift / (sizeof(byte) * 8); //Adjusted after @dasblinkenlight's correction
int nBitShift = nShift % (sizeof(byte) * 8);
if (nByteShift >= arr.Length)
nByteShift %= arr.Length;
int s = arr.Length - 1;
int d = s - nByteShift;
for (int nCnt = 0; nCnt < arr.Length; nCnt++, d--, s--)
{
while (d < 0)
d += arr.Length;
while (s < 0)
s += arr.Length;
byte byteS = arr[s];
resArr[d] |= (byte)(byteS << nBitShift);
resArr[d > 0 ? d - 1 : resArr.Length - 1] |= (byte)(byteS >> (sizeof(byte) * 8 - nBitShift));
}
}
return resArr;
}
and here's a test:
byte[] arr = new byte[] {
Convert.ToByte("11001110", 2),
Convert.ToByte("01000100", 2),
Convert.ToByte("10100001", 2),
};
byte[] arr2 = Auth.ROL_ByteArray(arr, 1);
string sss = "";
for (int i = 0; i < arr2.Length; i++)
sss += Convert.ToString(arr2[i], 2) + ", ";
Debug.WriteLine(sss);
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