在倾斜变换后获取SVG元素的宽度和高度 - javascript [英] getting the width and height of SVG element after skew transformation - javascript
问题描述
我有一个具有以下属性的 SVG rect
:
I have an SVG rect
with the following atributes:
<rect x="50" y="10" width="20" height="30" style="stroke: #000000; fill:none;" />
如果我应用 skewX(10)
转换,矩形的宽度和高度会发生变化.然后我如何使用普通的 javascript(没有库)计算它的真实宽度和高度?
If I apply a skewX(10)
tranformation, the width and height of the rectangle change. How do I then calculate its true width and height using plain javascript (without libraries)?
推荐答案
将
包裹在
元素中;然后获得对该组的引用;然后在其上调用 getBBox()
.
Wrap the <rect>
in a <g>
element; then get a reference to the group; then call getBBox()
on it.
var bbox = document.getElementById("wrapper").getBBox();;
alert("width=" + bbox.width + " height=" + bbox.height);
<svg>
<g id="wrapper">
<rect x="50" y="10" width="20" height="30" style="stroke: #000000; fill:none;"
transform="skewX(10)" />
</g>
</svg>
我们将元素包装在一个组中的原因是因为 getBBox()
返回的边界框不包括变换的效果.此外,它不必是
它可以是
的任何父元素,只要没有其他子元素可能会影响边界.
The reason we wrap the element in a group is because the bounding box returned by getBBox()
does not include the effects of the transform. Also, it doesn't have to be a <g>
it could be any parent of the <rect>
, as long as there are no other child elements that could affect the bounds.
或者你可以像斯蒂芬建议的那样使用三角函数.
Or you could use trigonometry like Stephen suggests.
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